Limits and Continuity
🟢 Lite — Quick Review (1h–1d)
Rapid summary for last-minute revision before your ECAT exam.
Limits:
The limit $\lim_{x \to a} f(x) = L$ means that as $x$ gets arbitrarily close to $a$, $f(x)$ gets arbitrarily close to $L$.
Standard Limits:
| Form | Limit |
|---|---|
| $\lim_{x \to 0} \frac{\sin x}{x}$ | $1$ |
| $\lim_{x \to 0} \frac{1 - \cos x}{x^2}$ | $\frac{1}{2}$ |
| $\lim_{x \to 0} \frac{e^x - 1}{x}$ | $1$ |
| $\lim_{x \to 0} \frac{\ln(1+x)}{x}$ | $1$ |
| $\lim_{x \to 0} \frac{a^x - 1}{x}$ | $\ln a$ |
| $\lim_{x \to \infty} (1 + \frac{1}{x})^x$ | $e$ |
| $\lim_{x \to 0} (1+x)^{1/x}$ | $e$ |
Indeterminate Forms: $\frac{0}{0}$, $\frac{\infty}{\infty}$, $0 \times \infty$, $\infty - \infty$, $0^0$, $\infty^0$, $1^\infty$
L’Hôpital’s Rule: For $\frac{0}{0}$ or $\frac{\infty}{\infty}$, if $\lim \frac{f’(x)}{g’(x)}$ exists: $$\lim_{x \to a} \frac{f(x)}{g(x)} = \lim_{x \to a} \frac{f’(x)}{g’(x)}$$
Continuity:
A function $f(x)$ is continuous at $x = a$ if:
- $f(a)$ is defined
- $\lim_{x \to a} f(x)$ exists
- $\lim_{x \to a} f(x) = f(a)$
⚡ ECAT exam tips:
- Direct substitution first — if it gives a finite number, that’s the limit
- If it gives $0/0$, try to factor and cancel, or use L’Hôpital’s rule
- For trigonometric limits: always try to convert to $\sin x / x$ form
- For $x \to \infty$ in rational functions: divide numerator and denominator by the highest power of $x$
🟡 Standard — Regular Study (2d–2mo)
For ECAT students who want genuine understanding.
Limit by Factorisation:
Example: $\lim_{x \to 2} \frac{x^2 - 4}{x - 2} = \lim_{x \to 2} \frac{(x-2)(x+2)}{x-2} = \lim_{x \to 2} (x+2) = 4$.
Example: $\lim_{x \to 1} \frac{x^3 - 1}{x^2 - 1} = \lim_{x \to 1} \frac{(x-1)(x^2+x+1)}{(x-1)(x+1)} = \lim_{x \to 1} \frac{x^2+x+1}{x+1} = \frac{3}{2}$.
Limit by Rationalising:
Example: $\lim_{x \to 0} \frac{\sqrt{x+1} - 1}{x} = \lim_{x \to 0} \frac{(\sqrt{x+1} - 1)(\sqrt{x+1} + 1)}{x(\sqrt{x+1} + 1)} = \lim_{x \to 0} \frac{x}{x(\sqrt{x+1}+1)} = \frac{1}{2}$.
Using $\sin x / x \to 1$:
Example: $\lim_{x \to 0} \frac{\sin 3x}{x} = \lim_{x \to 0} \frac{\sin 3x}{3x} \cdot 3 = 3$.
Example: $\lim_{x \to 0} \frac{\tan x}{x} = \lim_{x \to 0} \frac{\sin x}{x \cos x} = \frac{1 \cdot 1}{1} = 1$.
Limit at Infinity for Rational Functions:
For $\lim_{x \to \infty} \frac{ax^m + …}{bx^n + …}$:
- If $m < n$: limit = $0$
- If $m = n$: limit = $a/b$
- If $m > n$: limit = $\pm\infty$ (sign depends on leading coefficients)
Continuity — Types of Discontinuity:
-
Removable discontinuity: $\lim_{x \to a} f(x)$ exists but is not equal to $f(a)$ — can be “fixed” by redefining $f(a)$. Example: $f(x) = \frac{x^2-1}{x-1}$ at $x=1$: limit = $2$, but $f(1)$ undefined.
-
Jump discontinuity: left and right limits exist but are different. Example: $f(x) = \begin{cases} x & x < 0 \ x+1 & x \geq 0 \end{cases}$ at $x=0$: left limit = $0$, right limit = $1$.
-
Infinite discontinuity: limit is infinite. Example: $f(x) = 1/x$ at $x=0$: $\lim_{x \to 0^+} 1/x = +\infty$, $\lim_{x \to 0^-} 1/x = -\infty$.
⚡ Common student mistakes:
- Applying L’Hôpital’s rule to non-indeterminate forms
- Forgetting that L’Hôpital’s rule can be applied repeatedly (but check if the new limit is determinate)
- Using $\sin x / x \to 1$ with degrees instead of radians — this formula requires $x$ in radians
- Forgetting to check if the function is defined at the limit point for continuity
🔴 Extended — Deep Study (3mo+)
Comprehensive coverage for ECAT mastery of limits and continuity.
Formal Definition of Limit (ε-δ):
$\lim_{x \to a} f(x) = L$ means: for every $\varepsilon > 0$, there exists $\delta > 0$ such that if $0 < |x-a| < \delta$, then $|f(x) - L| < \varepsilon$.
While ECAT rarely requires this definition, understanding it clarifies what “approaching” means mathematically.
Sandwich (Squeeze) Theorem:
If $g(x) \leq f(x) \leq h(x)$ near $a$ and $\lim_{x \to a} g(x) = \lim_{x \to a} h(x) = L$, then $\lim_{x \to a} f(x) = L$.
Example: $\lim_{x \to 0} x^2 \sin(1/x) = 0$ because $-x^2 \leq x^2 \sin(1/x) \leq x^2$ and both $-x^2$ and $x^2$ tend to $0$.
Exponential and Logarithmic Limits:
$$\lim_{x \to 0} \frac{e^x - 1}{x} = 1$$ $$\lim_{x \to 0} \frac{a^x - 1}{x} = \ln a$$ $$\lim_{x \to 0} \frac{\ln(1+x)}{x} = 1$$ $$\lim_{x \to 0} (1+x)^{1/x} = e$$ $$\lim_{x \to \infty} \left(1 + \frac{k}{x}\right)^x = e^k$$
Using Standard Limits for More Complex Ones:
Example: $\lim_{x \to 0} \frac{e^{2x} - 1}{\sin 3x} = \lim_{x \to 0} \frac{e^{2x} - 1}{2x} \cdot \frac{3x}{\sin 3x} \cdot \frac{2}{3} = \frac{2}{3}$.
Example: $\lim_{x \to 0} (1 + \sin x)^{1/x} = e^{\lim_{x \to 0} \frac{\ln(1+\sin x)}{x}} = e^{\lim_{x \to 0} \frac{\cos x}{1+\sin x} \cdot \frac{1}{1}}$ by L’Hôpital… wait: $\frac{\ln(1+\sin x)}{x}$ is $0/0$. $\frac{d}{dx}\ln(1+\sin x) = \frac{\cos x}{1+\sin x}$. At $x=0$: $\frac{1}{1} = 1$. So the limit = $e^1 = e$.
One-sided Limits:
- Left-hand limit: $\lim_{x \to a^-} f(x) = L_1$
- Right-hand limit: $\lim_{x \to a^+} f(x) = L_2$
- If $L_1 = L_2 = L$, the two-sided limit $\lim_{x \to a} f(x) = L$ exists
Continuity on an Interval:
$f(x)$ is continuous on $(a,b)$ if it is continuous at every point in $(a,b)$. $f(x)$ is continuous on $[a,b]$ if it is continuous on $(a,b)$ and $\lim_{x \to a^+} f(x) = f(a)$ and $\lim_{x \to b^-} f(x) = f(b)$.
Intermediate Value Theorem:
If $f$ is continuous on $[a,b]$ and $f(a)$ and $f(b)$ have opposite signs (or one is zero), then there exists at least one $c \in (a,b)$ such that $f(c) = 0$. This is useful for finding approximate roots.
ECAT Previous Year Patterns:
- Standard limits: very common
- Factorisation and rationalisation: common
- L’Hôpital’s rule: common
- Continuity: common
- Limits at infinity: periodic
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📐 Diagram Reference
Mathematical diagram showing Limits and Continuity concept with coordinate axes, labeled points, geometric shapes shaded appropriately, clean black and white style
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