Differential Equations Basics
🟢 Lite — Quick Review (1h–1d)
Rapid summary for last-minute revision before your exam.
A differential equation is an equation that contains a derivative of an unknown function. They are fundamental tools in engineering and physics for describing how things change over time or space.
Key Definitions
- Differential Equation: An equation involving a function and its derivatives. Example: $\frac{dy}{dx} = 3x^2$
- Order: The highest derivative present. $\frac{d^2y}{dx^2} + 5\frac{dy}{dx} = x$ is a second-order DE.
- Degree: The highest power of the highest order derivative (when expressed as a polynomial in derivatives).
- Ordinary Differential Equation (ODE): Contains only one independent variable. $\frac{dy}{dx} = x + y$
- Partial Differential Equation (PDE): Contains partial derivatives with respect to multiple variables.
First-Order Differential Equations
Type 1: Variable Separable
If the equation can be written as $f(x)dx = g(y)dy$, we separate variables and integrate: $$\frac{dy}{dx} = xy$$ $$\frac{1}{y}dy = x \cdot dx$$ $$\int \frac{1}{y}dy = \int x \cdot dx$$ $$\ln|y| = \frac{x^2}{2} + C$$
Type 2: Linear First-Order DE
Form: $\frac{dy}{dx} + P(x)y = Q(x)$
The integrating factor is: $\mu(x) = e^{\int P(x)dx}$
Solution: $y \cdot \mu(x) = \int Q(x) \cdot \mu(x)dx + C$
Example: Solve $\frac{dy}{dx} + 2y = e^{3x}$
Here $P(x) = 2$, $Q(x) = e^{3x}$ $\mu(x) = e^{\int 2dx} = e^{2x}$
Multiply both sides by $e^{2x}$: $e^{2x}\frac{dy}{dx} + 2e^{2x}y = e^{5x}$ $\frac{d}{dx}(ye^{2x}) = e^{5x}$ $ye^{2x} = \int e^{5x}dx = \frac{e^{5x}}{5} + C$ $y = \frac{e^{3x}}{5} + Ce^{-2x}$
⚡ ECAT Tips
- Always include the constant of integration $C$ when integrating.
- Check whether your solution satisfies the original equation by differentiating it back.
- For word problems, translate the rate condition directly into a differential equation.
🟡 Standard — Regular Study (2d–2mo)
Standard content for students with a few days to months.
Types of First-Order DEs and Their Solutions
Exact Differential Equations
An equation $M(x,y)dx + N(x,y)dy = 0$ is exact if: $$\frac{\partial M}{\partial y} = \frac{\partial N}{\partial x}$$
If exact, there exists a function $\psi(x,y)$ such that $d\psi = Mdx + Ndy = 0$: $\psi(x,y) = C$
Example: Check if $(2xy + y^2)dx + (x^2 + 2xy)dy = 0$ is exact.
$M = 2xy + y^2$, $\frac{\partial M}{\partial y} = 2x + 2y$ $N = x^2 + 2xy$, $\frac{\partial N}{\partial x} = 2x + 2y$
Since $\frac{\partial M}{\partial y} = \frac{\partial N}{\partial x}$, the equation is exact.
Integrate $M$ with respect to $x$: $\psi = \int (2xy + y^2)dx = x^2y + xy^2 + f(y)$
Differentiate with respect to $y$: $\frac{\partial \psi}{\partial y} = x^2 + 2xy + f’(y) = N = x^2 + 2xy$
So $f’(y) = 0$, thus $f(y) = C$
Therefore: $\psi(x,y) = x^2y + xy^2 = K$ Or: $xy(x + y) = K$
Homogeneous Differential Equations
A DE is homogeneous if $M(x,y)$ and $N(x,y)$ are both homogeneous functions of the same degree.
Solution method: Substitute $y = vx$, so $\frac{dy}{dx} = v + x\frac{dv}{dx}$
Example: Solve $\frac{dy}{dx} = \frac{x^2 + y^2}{xy}$
$\frac{dy}{dx} = \frac{x^2 + y^2}{xy} = \frac{x}{y} + \frac{y}{x}$
Let $y = vx$, then $\frac{dy}{dx} = v + x\frac{dv}{dx}$: $v + x\frac{dv}{dx} = \frac{1}{v} + v$ $x\frac{dv}{dx} = \frac{1}{v}$ $v \cdot dv = \frac{1}{x}dx$ $\frac{v^2}{2} = \ln|x| + C$ Substituting back: $\frac{y^2}{2x^2} = \ln|x| + C$
Bernoulli’s Equation
Form: $\frac{dy}{dx} + P(x)y = Q(x)y^n$
Let $z = y^{1-n}$: $\frac{dz}{dx} + (1-n)P(x)z = (1-n)Q(x)$
Second-Order Linear DEs
General form: $a\frac{d^2y}{dx^2} + b\frac{dy}{dx} + cy = f(x)$
Complementary Function (CF): Solve $ay” + by’ + cy = 0$
Assume $y = e^{mx}$: $am^2 + bm + c = 0$
Three cases based on discriminant $b^2 - 4ac$:
- Distinct real roots ($b^2 > 4ac$): $y_c = Ae^{m_1x} + Be^{m_2x}$
- Equal real roots ($b^2 = 4ac$): $y_c = (A + Bx)e^{mx}$
- Complex roots ($b^2 < 4ac$): $y_c = e^{\alpha x}(A\cos\beta x + B\sin\beta x)$
Particular Integral (PI): Based on $f(x)$ form:
- $f(x) = e^{kx}$ → try $y_p = Ce^{kx}$ (if $k$ not a root, multiply by $x$ if it is)
- $f(x) = x^n$ → try $y_p = Ax^n + Bx^{n-1} + …$
- $f(x) = \sin(kx)$ or $\cos(kx)$ → try $y_p = P\sin(kx) + Q\cos(kx)$
General Solution: $y = y_c + y_p$
🔴 Extended — Deep Study (3mo+)
Comprehensive coverage for students on a longer study timeline.
Advanced DE Solution Methods
Method of Undetermined Coefficients
For linear DEs with constant coefficients, guess a particular solution based on the form of $f(x)$.
| $f(x)$ form | Trial particular solution |
|---|---|
| $e^{kx}$ | $Ce^{kx}$ (multiply by $x$ if $k$ is root) |
| $x^n$ | $A_nx^n + A_{n-1}x^{n-1} + … + A_0$ |
| $\sin(kx)$ or $\cos(kx)$ | $P\sin(kx) + Q\cos(kx)$ |
| $e^{kx}\sin(mx)$ | $e^{kx}(P\cos(mx) + Q\sin(mx))$ |
Example: Find the particular integral of $y” - 5y’ + 6y = e^{2x}$.
The auxiliary equation: $m^2 - 5m + 6 = 0$ $(m-2)(m-3) = 0$, so $m = 2, 3$
Since $k = 2$ is a root of the auxiliary equation, multiply by $x$: Try $y_p = Axe^{2x}$ $y_p’ = Ae^{2x} + 2Axe^{2x} = e^{2x}(A + 2Ax)$ $y_p” = 2Ae^{2x} + 2Ae^{2x} + 4Axe^{2x} = e^{2x}(4A + 4Ax)$
Substitute into LHS: $(4A + 4Ax) - 5(A + 2Ax) + 6(Ax) = e^{2x}$ $4A + 4Ax - 5A - 10Ax + 6Ax = e^{2x}$ $4A - 5A + (4A - 10A + 6A)x = e^{2x}$ $-A = e^{2x}$
This gives $A = -1$, so $y_p = -xe^{2x}$
Variation of Parameters
More general method for second-order linear DEs where method of undetermined coefficients fails.
For $y” + P(x)y’ + Q(x)y = R(x)$: Find CF: $y_c = u_1y_1 + u_2y_2$
Let $u_1’ = -\frac{y_2R}{W}$, $u_2’ = \frac{y_1R}{W}$
Where Wronskian $W = y_1y_2’ - y_1’y_2$
Particular solution: $y_p = -y_1\int\frac{y_2R}{W}dx + y_2\int\frac{y_1R}{W}dx$
Cauchy-Euler (Equidimensional) Equations
Form: $ax^2y” + bxy’ + cy = f(x)$
Try solution $y = x^m$: $m(m-1) + bm + c = 0$
Applications of Differential Equations
Population Growth (Malthusian): $$\frac{dP}{dt} = kP \Rightarrow P = P_0e^{kt}$$
Logistic Growth: $$\frac{dP}{dt} = kP(M - P) \Rightarrow P = \frac{M}{1 + Ae^{-kMt}}$$
Newton’s Law of Cooling: $$\frac{dT}{dt} = -k(T - T_s) \Rightarrow T = T_s + (T_0 - T_s)e^{-kt}$$
Electrical Circuits (RLC): For an RLC circuit: $L\frac{dI}{dt} + RI + \frac{q}{C} = E(t)$
Damped Oscillations: $m\frac{d^2x}{dt^2} + c\frac{dx}{dt} + kx = 0$
- Underdamped ($c^2 < 4mk$): $x = e^{-\alpha t}(A\cos\beta t + B\sin\beta t)$
- Critically damped ($c^2 = 4mk$): $x = (A + Bt)e^{-\alpha t}$
- Overdamped ($c^2 > 4mk$): $x = Ae^{m_1t} + Be^{m_2t}$
ECAT Engineering Context
In ECAT, differential equations often appear in:
- Calculating current in electrical circuits with resistors and capacitors
- Analysing spring-mass systems with damping
- Heat transfer problems (Newton’s law of cooling)
- Population dynamics and growth models
Working Tips
- Always check initial/boundary conditions to find constants.
- For non-homogeneous DEs, find the general solution of the homogeneous part first.
- Verify your solution by substituting back into the original DE.
- In engineering applications, the physical context suggests what type of solution to expect (oscillatory, decaying, growing).
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