Circle Geometry: Angles and Chords
🟢 Lite — Quick Review (1h–1d)
Rapid summary for last-minute revision before your exam.
A chord is a line segment joining two points on a circle, while an angle at the centre is twice the angle at the circumference subtended by the same arc. The angle in a semicircle is always 90°, and a cyclic quadrilateral has opposite angles summing to 180°.
- Centre-to-circumference ratio: θ_centre = 2 × θ_circumference (same arc).
- Angle in alternate segment: ∠ between tangent and chord = angle in opposite segment.
- Sector area: A = ½ r² θ (θ in radians); convert degrees × π/180 first.
🟡 Standard — Regular Study (2d–2mo)
Standard content for students with a few days to months.
Core Angle Theorems
Three theorems drive nearly every NECO question on this topic. First, the central angle theorem: an arc’s angle at the centre is twice its angle on the remaining circumference. Second, the angle in a semicircle is a right angle, valid only when the chord subtending it is the diameter. Third, angles in the same segment are equal because they stand on the same arc.
For tangent–chord contact, the angle between the tangent and the chord equals the angle in the alternate segment (the segment on the opposite side of the chord), not the same side.
| Theorem | Statement | Typical use |
|---|---|---|
| Centre vs circumference | ∠centre = 2 × ∠circumference | Find one when the other is known |
| Angle in semicircle | Chord is diameter ⇒ ∠ = 90° | Spot a right-angle triangle inside the circle |
| Same segment | Angles on same arc are equal | Prove two angles congruent |
| Alternate segment | Tangent–chord ∠ = ∠ in opposite segment | Combine with inscribed angle theorems |
| Cyclic quadrilateral | Opposite angles sum to 180° | Find a missing angle in a 4-point figure |
Chord Properties and Equal-Arcs Rule
Equal chords subtend equal arcs and equal angles at the centre; conversely, equal central angles or equal arcs imply equal chords. A perpendicular drawn from the centre to any chord bisects that chord, and the line joining the centre to a chord’s midpoint is always perpendicular to the chord.
- Convert θ from degrees to radians before applying A = ½ r² θ or A_segment = ½ r² (θ − sin θ).
- Distinguish major arc (> 180°) from minor arc (< 180°) when the problem specifies which arc the angle stands on.
- The exterior angle of a cyclic quadrilateral equals the interior opposite angle, a quick shortcut in multi-step proofs.
🔴 Extended — Deep Study (3mo+)
Comprehensive coverage for students on a longer study timeline.
Worked Example
A circle has radius r = 7 cm and a chord subtends a central angle of 60°. Find the chord length and the area of the minor segment.
Step 1 — chord length. The chord and two radii form an isosceles triangle with vertex angle 60°. Split it into two right triangles; the half-angle is 30°. So half-chord = 7 sin 30° = 3.5, giving chord = 7 cm.
Step 2 — sector area. Convert: θ = 60° = π/3 rad. A_sector = ½ × 49 × π/3 = 49π/6 cm² ≈ 25.66 cm².
Step 3 — segment area. Triangle area = ½ × 7 × 7 × sin 60° = 49√3/4 ≈ 21.22 cm². So A_segment = 25.66 − 21.22 ≈ 4.44 cm².
Edge Cases and Exam Traps
| Trap | Correct handling |
|---|---|
| Mixing sector with segment formulas | Segment = sector − triangle, only when θ ≤ 180° |
| Using degrees in r² formulas | Multiply degrees by π/180 first |
| Inscribed angle on the major arc | The angle is still half the (reflex) central angle |
| Tangent–chord angle wrong segment | It matches the alternate segment, not the same one |
| Confusing chord length with arc length | Chord = 2r sin(θ/2); arc = rθ (radians) |
Practice prompts.
- A chord AB subtends 80° at the circumference. Find the angle subtended at the centre and the angle in the alternate segment where a tangent at A meets AB.
- In cyclic quadrilateral PQRS, ∠P = (2x + 10)° and ∠R = (4x − 20)°. Solve for x and confirm ∠Q + ∠S = 360° − 180°.
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Sources & verification
- Official NECO SSCE syllabus & pattern: https://www.negov.org
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- Reviewed by Pushkar Saini · last updated
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