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Subject Specific 3% exam weight

Thermodynamic Cycles and Steam Turbines

Part of the GATE study roadmap. Subject Specific topic subjec-002 of Subject Specific.

Thermodynamic Cycles and Steam Turbines

Power cycles are a staple of the GATE ME and XE papers. The Rankine cycle dominates steam turbine questions, while the Brayton, Otto, and Diesel cycles appear in gas turbine and IC engine contexts. Expect 3–8 marks from this topic annually, with cycle analysis and efficiency calculations being the most frequent question types.


🟢 Lite — Quick Review (1h–1d)

Rapid summary for last-minute revision before your exam.

Rankine Cycle — The Steam Power Cycle

Four processes: Pump → Boiler → Turbine → Condenser → Pump (back to boiler)

ComponentProcessEnergy Change
PumpIsentropic compressionWork input (small)
BoilerConstant pressure heat addition$q_{in} = h_3 - h_1$
TurbineIsentropic expansionWork output $w_T = h_3 - h_4$
CondenserConstant pressure heat rejection$q_{out} = h_4 - h_1$

$$\eta_{Rankine} = \frac{w_{net}}{q_{in}} = \frac{(h_3 - h_4) - (h_2 - h_1)}{h_3 - h_2}$$

Key Modifications:

  • Reheating: Increases average temp of heat addition → higher efficiency
  • Regeneration: Feedwater heating → reduces fuel requirement
  • Supercritical: Boiler pressure above critical point (22.06 MPa) → no boiling transition

Brayton Cycle (Gas Turbine) $$\eta = 1 - \frac{T_1}{T_2} = 1 - r_p^{(\gamma-1)/\gamma}$$ Where $r_p = P_2/P_1$ is pressure ratio.

Otto Cycle (SI Engines): $\eta = 1 - \frac{1}{r^{\gamma-1}}$ where $r = V_1/V_2$ (compression ratio)

Diesel Cycle: $\eta = 1 - \frac{1}{\gamma}\cdot\frac{r^\gamma - 1}{r - 1}\cdot\frac{1}{cutoff\text{-}ratio^{\gamma-1}}$

Exam Tip: Rankine cycle is almost always paired with steam tables in GATE — memorize how to read $h, s$ values.


🟡 Standard — Regular Study (2d–2mo)

Standard content for students with a few days to months.

Rankine Cycle — Detailed Analysis

The Rankine cycle is the ideal cycle for steam power plants. Unlike Carnot, it uses turbines that expand steam isentropically (rather than isothermally, which is impractical).

T-s Diagram Key Points

  • Pump work is small relative to turbine work (visually, the pump leg is nearly vertical)
  • Boiler heat addition appears as area under the curve between saturated liquid and superheated steam
  • Turbine work is the drop across the turbine
  • Condenser rejection is the horizontal line at low pressure

Rankine vs Carnot Efficiency

RankineCarnot
Turbine exhaust is wet steamRequires isothermal expansion (impractical)
Pump work is smallPump work would be large
Easier to constructIdeal but not realizable

The Carnot efficiency $\eta = 1 - T_L/T_H$ is a theoretical maximum. Rankine approaches it but cannot equal it because the turbine exhaust contains moisture (wet steam) rather than saturated vapor.

Reheat Cycle

Purpose: Reduce turbine exit moisture and increase efficiency.

Two turbine stages with reheating between them:

  • High-pressure turbine expands steam to an intermediate pressure
  • Steam is reheated in the boiler (or reheater)
  • Low-pressure turbine expands to condenser pressure

Efficiency improvement: Reheat increases average temperature of heat rejection → higher cycle efficiency, but with diminishing returns beyond 2–3 reheat stages.

Regenerative Cycle

Feedwater heating uses extracted steam to preheat the feedwater, reducing the amount of heat required in the boiler.

Open feedwater heater: Extracted steam mixes directly with feedwater (isenthalpic mixing).

Closed feedwater heater: Extracted steam condenses on tube exterior, transferring heat without mixing.

Efficiency impact: Regeneration increases cycle efficiency by reducing the $q_{in}$ requirement, but reduces net work output since some steam is bled before doing full work in the turbine.

Supercritical Rankine Cycle

Operating above the critical pressure (22.06 MPa, 374°C):

  • No distinct phase transition (no boiling)
  • Water directly goes from liquid to supercritical fluid
  • Higher thermal efficiency (typically 40–45% for modern plants)
  • Requires specialized materials due to high pressures and temperatures

Brayton Cycle — Gas Turbines

The Brayton cycle consists of:

  1. Isentropic compression (compressor)
  2. Constant pressure heat addition (combustion chamber)
  3. Isentropic expansion (turbine)
  4. Constant pressure heat rejection (exhaust)

$$\eta_{Brayton} = 1 - \left(\frac{P_2}{P_1}\right)^{(\gamma-1)/\gamma} = 1 - \frac{T_1}{T_2}$$

Key observations:

  • Higher pressure ratio → higher efficiency, but also higher turbine inlet temperature
  • $T_3$ (turbine inlet temp) is limited by material constraints (~1200–1500 K)
  • Gas turbine requires regeneration for efficiency gains at low pressure ratios

Deviation from Ideal Brayton

Component efficiencies:

  • Compressor: $\eta_c = (T_{2s} - T_1)/(T_2 - T_1)$
  • Turbine: $\eta_t = (T_3 - T_4)/(T_3 - T_{4s})$

Where $s$ denotes isentropic conditions.

Otto and Diesel Cycles

Both are air-standard cycles for reciprocating engines.

Otto Cycle (Spark Ignition)

  • Constant volume heat addition
  • Compression ratio $r = V_1/V_2$ determines efficiency
  • $\eta_{Otto} = 1 - r^{-(\gamma-1)}$
  • Higher compression ratio → higher efficiency (but limited by knocking in SI engines)

Diesel Cycle (Compression Ignition)

  • Constant pressure heat addition (idealized)
  • Cut-off ratio $\rho = V_3/V_2$ affects efficiency
  • $\eta_{Diesel} = 1 - \frac{1}{\gamma}\cdot\frac{r^\gamma - 1}{(\rho - 1)r^{\gamma-1}}$
  • Diesel engines typically have higher thermal efficiency than Otto engines

⚡ Common Mistake: Students confuse compression ratio and cut-off ratio. In Diesel cycle, efficiency decreases with increasing cut-off ratio (more heat added at constant pressure).

CycleHeat AdditionHeat RejectionTypical Use
OttoConstant VConstant VSI engines
DieselConstant PConstant VCI engines
DualV + PConstant VModern engines

🔴 Extended — Deep Study (3mo+)

Comprehensive coverage for students on a longer study timeline.

Combined Cycles and Advanced Concepts

Combined Gas-Vapor (Rankine + Brayton)

Combined cycle power plant uses Brayton cycle topping and Rankine cycle bottoming:

  • Gas turbine exhaust heat generates steam in HRSG (Heat Recovery Steam Generator)
  • Steam turbine produces additional power
  • Combined efficiency: 50–60% (vs ~35% for standalone cycles)

This is the dominant technology in modern power generation.

Binary Vapor Cycles (Mercury-Water)

Historical concept using mercury (boiling at higher temp) as working fluid in a topping cycle, with steam as bottoming cycle. Largely superseded by combined gas-vapor cycles.

Rankine Cycle with Superheat, Reheat, and Regeneration

For a complete Rankine cycle with superheat, reheat, and feedwater heating:

Steam properties needed from steam tables:

  • Saturated liquid line: $h_f$, $s_f$
  • Saturated vapor line: $h_g$, $s_g$
  • Superheated steam: interpolate in tables for given $P, T$

Isentropic expansion in turbine: $$s_3 = s_4 \implies \text{Find } h_4 \text{ using steam tables}$$

If $s_3 > s_g$ at turbine exit pressure → mixture (use $x_4$ quality) $$h_4 = h_f + x_4(h_g - h_f)$$

Brayton Cycle — Regeneration Effects

With regeneration (heat exchanger using turbine exhaust to preheat compressed air):

  • Reduces fuel consumption
  • Effective at low pressure ratios
  • Maximum benefit when $T_4 \approx T_2$ (turbine exit temp equals compressor exit temp)

Optimum pressure ratio for maximum specific work (no regeneration): $$\left(\frac{P_2}{P_1}\right)_{opt} = \left(\frac{T_3}{T_1}\right)^{\gamma/[2(\gamma-1)]}$$

Example Problem

GATE 2021 (ME) Style: In a Rankine cycle, steam enters the turbine at 10 MPa, 500°C and condenses at 0.1 bar. Find the cycle efficiency and turbine exit quality.

Solution approach:

  1. At turbine inlet (state 3): $h_3, s_3$ from superheated steam tables at 10 MPa, 500°C
  2. Isentropic expansion: $s_3 = s_4$ at 0.1 bar → find $h_4$
    • If $s_4 < s_g$ at 0.1 bar → quality $x_4 = (s_4 - s_f)/s_{fg}$
    • $h_4 = h_f + x_4 \cdot h_{fg}$
  3. Pump work: $h_2 - h_1 \approx v_f \Delta P$ (approximately, for incompressible liquid)
  4. Efficiency: $\eta = [(h_3 - h_4) - (h_2 - h_1)]/(h_3 - h_2)$

⚡ GATE Tip: Always check if turbine exit quality is acceptable (should be > ~85-90% for most designs). Low quality causes cavitation in the condenser.

Summary Table — Cycle Efficiencies

CycleMaximum EfficiencyLimiting Factor
Carnot$1 - T_L/T_H$Requires isothermal expansion
RankineLower than CarnotMoisture in turbine exhaust
Brayton$1 - T_1/T_2$Material temp limit $T_3$
Otto$1 - r^{-(\gamma-1)}$Knocking, compression ratio
DieselLower than OttoCut-off ratio

Previous Year GATE Pattern

YearTopic FocusMarks
2023Rankine with reheat, efficiency5
2022Brayton cycle, pressure ratio2
2021Otto vs Diesel efficiency3
2020Combined cycle2

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