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General Aptitude 3% exam weight

Topic 5

Part of the GATE study roadmap. General Aptitude topic genera-005 of General Aptitude.

Geometry and Mensuration

Geometry in GATE’s General Aptitude section tests your ability to visualize shapes, apply area/volume formulas, and use properties of similar figures. Mensuration (3D geometry) is a perennial favorite — the formulas are fixed, and so are the ways GATE tricks you.


🟢 Lite — Quick Review (1h–1d)

Must-know formulas:

  • Triangle: Area = ½ × base × height; Perimeter = a + b + c
  • Circle: Area = πr²; Circumference = 2πr
  • Rectangle: Area = l × w; Perimeter = 2(l + w)
  • Cube: Volume = a³; Surface area = 6a²
  • Cylinder: Volume = πr²h; Curved SA = 2πrh; Total SA = 2πr(r + h)
  • Sphere: Volume = (4/3)πr³; Surface area = 4πr²
  • Pythagorean theorem: a² + b² = c² (for right-angled triangles)

⚡ GATE exam tip: When a problem mentions “the area of a semicircle,” the formula is (1/2)πr² — don’t forget the π. GATE often tests whether you retain π or approximate it as 22/7.

⚡ Quick trick: In an isosceles triangle with equal sides a and base b, the height = √(a² − b²/4). Use this when asked for area or altitude.

⚡ Common trap: Don’t confuse curved surface area (lateral surface) with total surface area. For a cone, CSA = πrl, TSA = πr(r + l).


🟡 Standard — Regular Study (2d–2mo)

Triangles

Classification by sides:

  • Equilateral: all sides equal, all angles = 60°
  • Isosceles: two sides equal
  • Scalene: all sides different

Area formulas:

  • ½ × base × height
  • Heron’s formula: √[s(s−a)(s−b)(s−c)] where s = (a+b+c)/2 (semiperimeter)
  • For equilateral triangle of side a: Area = (√3/4)a²

Right-angled triangle (Pythagorean triples):

SetRatio
3-4-53:4:5
5-12-135:12:13
7-24-257:24:25
8-15-178:15:17

GATE Example (2019, 1 mark): Find the area of a triangle with sides 9, 10, and 17 cm.

s = (9+10+17)/2 = 18. Area = √[18×9×8×1] = √1296 = 36 cm². (Note: 9²+10²=181 ≠ 289=17², so not right-angled.)

Similar triangles: If two triangles are similar, the ratio of their areas = (ratio of corresponding sides)².

Circles

  • Area: πr²
  • Circumference: 2πr
  • Arc length: (θ/360) × 2πr (where θ is the central angle in degrees)
  • Sector area: (θ/360) × πr²

GATE Example: A circle has radius 7 cm. Find the area of a sector with a 60° angle.

Area = (60/360) × π × 7² = (1/6) × 22/7 × 49 = 77/3 ≈ 25.67 cm².

Polygons

Regular n-gon:

  • Each interior angle = [(n−2) × 180°] / n
  • Each exterior angle = 360°/n
  • Sum of interior angles = (n−2) × 180°

Key polygons to know:

PolygonNumber of sidesSum of angles
Triangle3180°
Quadrilateral4360°
Pentagon5540°
Hexagon6720°

3D Mensuration — Key Solids

Cube (side a):

  • Volume = a³
  • Surface area = 6a²
  • Diagonal = a√3

Cuboid (l × b × h):

  • Volume = l × b × h
  • Surface area = 2(lb + bh + hl)
  • Diagonal = √(l² + b² + h²)

Cylinder (radius r, height h):

  • Volume = πr²h
  • Curved surface area = 2πrh
  • Total surface area = 2πr(r + h)

Cone (radius r, height h, slant height l):

  • l = √(r² + h²)
  • Volume = (1/3)πr²h
  • Curved surface area = πrl
  • Total surface area = πr(r + l)

Sphere (radius r):

  • Volume = (4/3)πr³
  • Surface area = 4πr²

GATE Example (2017, 1 mark): The total surface area of a cube is 216 cm². Find its volume.

6a² = 216 → a² = 36 → a = 6 cm. Volume = 6³ = 216 cm³.


🔴 Extended — Deep Study (3mo+)

Similar Figures — Area and Volume Ratios

Important principle: When two similar figures have corresponding sides in ratio k:1, then:

  • Their areas are in ratio k²:1
  • Their volumes are in ratio k³:1

GATE Advanced Example: Two spheres have radii in the ratio 2:3. Find the ratio of their volumes.

Volume ratio = (2³):(3³) = 8:27.

Prism and Pyramid

Right Prism:

  • Volume = Base area × height
  • Lateral surface area = Perimeter of base × height

Regular Pyramid:

  • Volume = (1/3) × Base area × height
  • Lateral surface area = (1/2) × Perimeter of base × slant height

Frustum of a Cone

When a cone is sliced parallel to its base, the remaining portion is a frustum:

  • Volume = (1/3)πh(R² + r² + Rr) where R and r are the radii of the two bases
  • CSA = π(R + r) × slant height (where slant height = √[h² + (R−r)²])

Hemisphere

Hemisphere (radius r):

  • Volume = (2/3)πr³
  • Curved surface area = 2πr²
  • Total surface area = 3πr² (including the base circle)

Combination of Solids

When multiple solids are combined (e.g., a cone on top of a cylinder), add volumes and surface areas carefully — shared faces are NOT exposed in the total surface area.

GATE Example: A wooden article is made by scooping out a hemisphere from each end of a solid cylinder of height 14 cm and radius 3 cm. Find the remaining volume.

Cylinder volume = π×3²×14 = 126π. Two hemispheres = 1 full sphere = (4/3)π×3³ = 36π. Remaining = 126π − 36π = 90π cm³.

Coordinate Geometry Basics

Distance between two points (x₁, y₁) and (x₂, y₂):

d = √[(x₂−x₁)² + (y₂−y₁)²]

Section formula (internal division):

Point dividing line joining (x₁, y₁) and (x₂, y₂) in ratio m:n = ((mx₂ + nx₁)/(m+n), (my₂ + ny₁)/(m+n))

Midpoint = ((x₁+x₂)/2, (y₁+y₂)/2)

Area of triangle with vertices (x₁,y₁), (x₂,y₂), (x₃,y₃):

Area = ½|x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|

Pythagorean Theorem Applications

GATE trick: The converse of Pythagorean theorem also works: if a² + b² = c², the triangle is right-angled with c as the hypotenuse.

Distance from a point to a line:

Distance from (x₀, y₀) to Ax + By + C = 0 is |Ax₀ + By₀ + C| / √(A² + B²)

Angle Bisector Theorem

In triangle ABC, if AD bisects angle A (meeting BC at D):

BD/DC = AB/AC

Quadrilaterals

TypeProperties
ParallelogramOpposite sides parallel, opposite angles equal, diagonals bisect each other
RectangleParallelogram + right angles, diagonals equal
RhombusParallelogram + all sides equal, diagonals perpendicular
SquareRectangle + Rhombus
TrapeziumOne pair of parallel sides

Area of trapezium = ½(sum of parallel sides) × height


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