Number System
🟢 Lite — Quick Review (1h–1d)
Rapid summary for last-minute revision before your exam.
Number System — Key Facts for GAT Pakistan
Types of Numbers:
| Type | Definition | Example |
|---|---|---|
| Natural Numbers (N) | Counting numbers starting from 1 | 1, 2, 3, 4, … |
| Whole Numbers (W) | Natural numbers + 0 | 0, 1, 2, 3, … |
| Integers (Z) | Positive, negative, and zero | …, -2, -1, 0, 1, 2, … |
| Rational Numbers (Q) | Can be expressed as p/q where q≠0 | 1/2, 3/4, -5/6, 0.333 |
| Irrational Numbers | Cannot be expressed as p/q | √2, π, e |
| Real Numbers (R) | All rational + irrational | All numbers on number line |
Even and Odd Numbers:
- Even: Divisible by 2 → 2, 4, 6, 8, 10
- Odd: Not divisible by 2 → 1, 3, 5, 7, 9
- Properties:
- Even + Even = Even
- Odd + Odd = Even
- Even + Odd = Odd
- Even × Even = Even
- Odd × Odd = Odd
- Even × Odd = Even
Prime Numbers:
- Numbers divisible only by 1 and themselves
- First 10 primes: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29
- Note: 1 is NOT a prime number
- Only even prime: 2
⚡ GAT Exam Tip: For prime number questions, remember that 2 is the only even prime. All other primes are odd.
🟡 Standard — Regular Study (2d–2mo)
Standard content for students with a few days to months.
Number System — Detailed Study Guide
Divisibility Rules
| Divisor | Rule | Example |
|---|---|---|
| 2 | Last digit even (0, 2, 4, 6, 8) | 124 ✓, 137 ✗ |
| 3 | Sum of digits divisible by 3 | 126 → 1+2+6=9 ✓ |
| 4 | Last two digits divisible by 4 | 124 ✓ (24÷4=6) |
| 5 | Last digit 0 or 5 | 135 ✓ |
| 6 | Divisible by both 2 and 3 | 126 ✓ |
| 7 | Double last digit, subtract from rest | 203 → 20-6=14 ✓ |
| 8 | Last three digits divisible by 8 | 1248 ✓ |
| 9 | Sum of digits divisible by 9 | 126 → 1+2+6=9 ✓ |
| 10 | Last digit 0 | 120 ✓ |
| 11 | (Sum of odd positions) - (Sum of even positions) divisible by 11 | 2728: (2+7) - (7+8) = 9-15 = -6 ✗ |
GAT Worked Example:
Question: Is 1734 divisible by 3?
Solution:
Sum of digits = 1 + 7 + 3 + 4 = 15
15 ÷ 3 = 5 (exact)
Answer: Yes, 1734 is divisible by 3
⚡ Common Mistake: Students often forget that divisibility by 6 requires BOTH 2 and 3 conditions to be satisfied.
LCM and HCF
HCF (GCD - Greatest Common Divisor):
- Largest number that divides both numbers
- Method 1: Prime factorization
- Find prime factors of each number
- Take common factors with lowest power
- Method 2: Euclidean Algorithm
- Divide larger by smaller
- Replace larger with remainder
- Continue until remainder = 0
LCM (Least Common Multiple):
- Smallest number divisible by both numbers
- Method 1: Prime factorization
- Take highest power of each prime
- Method 2: LCM × HCF = Product of two numbers
Worked Examples:
Example 1: Find HCF and LCM of 24 and 36
Prime factorization:
24 = 2³ × 3
36 = 2² × 3²
HCF = 2² × 3 = 12
LCM = 2³ × 3² = 72
Verification: 24 × 36 = 864
HCF × LCM = 12 × 72 = 864 ✓
Example 2: Using Euclidean Algorithm
HCF of 72 and 48:
72 ÷ 48 = 1 remainder 24
48 ÷ 24 = 2 remainder 0
HCF = 24 ✓
⚡ GAT PYQ: “The HCF of 48, 72, and 96 is: (a) 24 (b) 12 (c) 48 (d) 96” → Answer: (a) 24
Fractions and Decimals
Types of Decimals:
| Type | Example | Conversion |
|---|---|---|
| Terminating | 0.25, 0.125 | Finite digits after decimal |
| Recurring | 0.333… | Repeating pattern |
| Non-terminating non-recurring | √2 = 1.414… | No pattern |
Fraction Conversions:
1/2 = 0.5
1/3 = 0.333... = 0.3̄
1/4 = 0.25
1/5 = 0.2
1/6 = 0.1666... = 0.16̄
1/8 = 0.125
1/9 = 0.111... = 0.1̄
1/10 = 0.1
To convert fraction to decimal: Divide numerator by denominator To convert decimal to fraction: Count decimal places, put over 10^n
🔴 Extended — Deep Study (3mo+)
Comprehensive coverage for students on a longer study timeline.
Number System — Complete Notes for GAT
Surds and Indices
Laws of Indices:
| Law | Formula | Example |
|---|---|---|
| Product | a^m × a^n = a^(m+n) | 2³ × 2⁴ = 2⁷ |
| Quotient | a^m ÷ a^n = a^(m-n) | 3⁵ ÷ 3² = 3³ |
| Power of power | (a^m)^n = a^(mn) | (2²)³ = 2⁶ |
| Zero exponent | a^0 = 1 (where a≠0) | 5⁰ = 1 |
| Negative exponent | a^(-n) = 1/a^n | 2^(-3) = 1/8 |
| Fractional exponent | a^(m/n) = n√(a^m) | 8^(2/3) = ³√(8²) = 4 |
Laws of Surds:
| Law | Formula | Example |
|---|---|---|
| Multiplication | √a × √b = √(ab) | √3 × √5 = √15 |
| Division | √a ÷ √b = √(a/b) | √15 ÷ √3 = √5 |
| Rationalization | √a × √a = a | √5 × √5 = 5 |
| Conjugate | (√a + √b)(√a - √b) = a - b | (√7+√3)(√7-√3) = 7-3=4 |
Worked Examples:
Example 1: Simplify ³√72
72 = 8 × 9 = 2³ × 3²
³√72 = ³√(2³ × 3²) = 2 × ³√9 = 2³√9
Example 2: Simplify (√3 + √2)(√3 - √2)
= (√3)² - (√2)²
= 3 - 2 = 1 ✓ (using difference of squares)
Example 3: Simplify 2√3 + 5√3 - 3√3
= (2 + 5 - 3)√3
= 4√3
⚡ Important for GAT: Always rationalize denominators when simplifying expressions with surds.
Number Theory Problems
Finding Number of Factors:
Example: Find the number of positive factors of 360
360 = 2³ × 3² × 5¹
Number of factors = (3+1)(2+1)(1+1)
= 4 × 3 × 2
= 24
The 24 factors are: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18,
20, 24, 30, 36, 40, 45, 60, 72, 90, 120, 180, 360
Perfect Numbers:
- A number equal to the sum of its proper divisors
- Example: 6 = 1 + 2 + 3 (proper divisors)
- Example: 28 = 1 + 2 + 4 + 7 + 14
- Next perfect number: 496, then 8128
Prime Factorization Applications:
Question: Find the largest 4-digit number divisible by 12, 15, and 18.
Solution:
12 = 2² × 3
15 = 3 × 5
18 = 2 × 3²
LCM = 2² × 3² × 5 = 180
Largest 4-digit number = 9999
9999 ÷ 180 = 55 remainder 99
9999 - 99 = 9900
Answer: 9900
GAT-Style Practice Questions
1. If a number leaves remainder 3 when divided by 5, and remainder 5 when
divided by 7, what is the least such number?
(a) 33 (b) 38 (c) 45 (d) 48
Answer: (a) 33
Solution: 33 ÷ 5 = 6 remainder 3 ✓
33 ÷ 7 = 4 remainder 5 ✓
2. The difference between the largest and smallest 3-digit numbers
divisible by 17 is:
(a) 884 (b) 867 (c) 952 (d) 999
Answer: (b) 867
Solution: Smallest 3-digit = 102 (17×6)
Largest 3-digit = 986 (17×58)
Difference = 986 - 102 = 884
(Wait, let me recalculate)
Smallest 3-digit divisible by 17: 17×6 = 102 ✓
Largest 3-digit divisible by 17: 17×58 = 986
17×59 = 1003 (4-digit)
Difference = 986 - 102 = 884
Answer should be (a) 884
3. How many prime numbers are between 1 and 50?
(a) 14 (b) 15 (c) 16 (d) 17
Answer: (b) 15
Primes: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47 = 15 primes
⚡ GAT Strategy: For divisibility questions, first check the conditions. For remainder questions, use the Chinese Remainder Theorem approach for multiple divisors.
Unit Digit Problems
Finding Unit Digits of Powers:
| Base Unit Digit | Pattern Cycle | Example |
|---|---|---|
| 0 | Always 0 | 0, 0, 0, … |
| 1 | Always 1 | 1, 1, 1, … |
| 2 | 2, 4, 8, 6 | 2^15 ends in 2^3 = 8 |
| 3 | 3, 9, 7, 1 | 3^15 ends in 3^3 = 7 |
| 4 | 4, 6 | 4^15 ends in 4 |
| 5 | Always 5 | 5, 5, 5, … |
| 6 | Always 6 | 6, 6, 6, … |
| 7 | 7, 9, 3, 1 | 7^15 ends in 7^3 = 3 |
| 8 | 8, 4, 2, 6 | 8^15 ends in 8^3 = 2 |
| 9 | 9, 1 | 9^15 ends in 9 |
Worked Example:
Find the unit digit of 7^23
Solution:
Cycle for 7: 7, 9, 3, 1 (every 4)
23 ÷ 4 = 5 remainder 3
Position 3 in cycle = 3
Answer: Unit digit = 3
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