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Chemistry 3% exam weight

Electronic Configuration and Periodicity

Part of the UNEB UACE (Uganda) study roadmap. Chemistry topic chemis-007 of Chemistry.

By Last updated 3% exam weight

Electronic Configuration and Periodicity

🟢 Lite — Quick Review (1h–1d)

Rapid summary for last-minute revision before your exam.

s-block elements occupy Groups 1 (alkali metals, Li→Fr) and 2 (alkaline earth metals, Be→Ra) of the periodic table, each with a general outer electronic configuration of ns¹ or ns² respectively. Down each group, atomic and ionic radii increase, first ionization energy decreases, and electronegativity decreases, so metallic character — and reactivity with water — rises. Group 1 metals form ionic, water-soluble hydroxides (MOH) that are strongly basic; Group 2 hydroxides M(OH)₂ are sparingly soluble, with solubility increasing down the group. Carbonates and nitrates of Group 2 become more thermally stable down the group because the larger cation polarises the anion less. Flame colours are diagnostic: Na = yellow, K = lilac, Li = crimson, Ca = brick-red, Ba = apple-green. The Solvay process (NaCl + CaCO₃ + NH₃ + CO₂) manufactures Na₂CO₃, while EDTA titration with Eriochrome Black T quantifies Ca²⁺/Mg²⁺ in hard water.


🟡 Standard — Regular Study (2d–2mo)

Standard content for students with a few days to months.

Electronic Configuration and Periodicity

All s-block metals have low ionisation energies because the outermost electron is well shielded by filled inner shells. Ionisation energy decreases down a group (larger atom, electron farther from nucleus) but increases across a period. Electronegativity follows the same downward-decreasing trend, which is why these elements readily lose electrons to form M⁺ (Group 1) and M²⁺ (Group 2) cations.

Reactions with Water

Reactivity with water increases down each group:

  • 2Na + 2H₂O → 2NaOH + H₂ (vigorous)
  • 2K + 2H₂O → 2KOH + H₂ (ignites, lilac flame)
  • Mg + 2H₂O → Mg(OH)₂ + H₂ (slow with cold water, faster with steam)
  • Ca + 2H₂O → Ca(OH)₂ + H₂ (moderately vigorous)

The corresponding oxides (Na₂O, CaO) dissolve in water to give hydroxides, e.g. Na₂O + H₂O → 2NaOH; CaO + H₂O → Ca(OH)₂ (slaking of lime).

Thermal Stability of Carbonates and Nitrates

For Group 2 carbonates, e.g. CaCO₃ → CaO + CO₂, the decomposition temperature rises down the group. A small, highly charged cation (Mg²⁺) strongly polarises the large CO₃²⁻ anion, distorting it and making decomposition easier; Ba²⁺ polarises CO₃²⁻ far less, so BaCO₃ needs much more heat to break down.

Solubility Contrasts

A commonly tested pair:

CompoundTrend down Group 2Reason
Hydroxides, M(OH)₂Solubility increasesDecreasing lattice energy dominates
Sulphates, MSO₄Solubility decreasesHydration enthalpy falls faster than lattice energy

Diagonal Relationship

Li resembles Mg (e.g. both form nitrides Li₃N and Mg₃N₂, and carbonates that decompose on heating), while Be resembles Al (amphoteric oxide and hydroxide, covalent chloride BeCl₂). The similarity arises because of comparable charge/size ratios across the diagonal.

The Solvay Process (Industrial Na₂CO₃)

Key stages:

  1. NH₃ + CO₂ + H₂O → NH₄HCO₃
  2. NH₄HCO₃ + NaCl → NaHCO₃↓ + NH₄Cl
  3. 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂ (calcination)
  4. CaCO₃ → CaO + CO₂ (recycled)
  5. CaO + H₂O → Ca(OH)₂; Ca(OH)₂ + 2NH₄Cl → CaCl₂ + 2NH₃ (NH₃ recovered)

Ammonia is recycled, so the net stoichiometry simplifies to: 2NaCl + CaCO₃ → Na₂CO₃ + CaCl₂

Hard Water

Temporary hardness (Ca(HCO₃)₂, Mg(HCO₃)₂) is removed by boiling: Ca(HCO₃)₂ → CaCO₃↓ + H₂O + CO₂. Permanent hardness (CaSO₄, MgSO₄, CaCl₂) requires washing soda (Na₂CO₃) or ion-exchange resin. Ca²⁺/Mg²⁺ in water are quantified by EDTA complexometric titration with Eriochrome Black T indicator (wine-red → blue at the end point).

Flame Tests

  • Li: crimson; Na: persistent yellow; K: lilac (viewed through cobalt-blue glass to mask Na); Rb: red; Cs: blue.
  • Ca: brick-red; Sr: crimson; Ba: apple-green.

Typical UACE Question Patterns

Paper 1 (structured) frequently asks for explanations of trends using ionisation energy, lattice energy, and hydration enthalpy, often through a Born–Haber cycle: ΔH_solution = ΔH_lattice + ΔH_hydration. Paper 2 essays test the Solvay process flow diagram, balancing equations, and stating reagents/conditions. Practical/oral questions test flame-test identification of an unknown alkali/alkaline earth salt and EDTA determination of total hardness.


🔴 Extended — Deep Study (3mo+)

Comprehensive coverage for students on a longer study timeline.

Born–Haber Treatment of s-Block Halides

The stability of an ionic solid such as NaCl is dissected into measurable steps: sublimation of Na, dissociation of Cl₂, ionisation of Na(g), electron attachment to Cl(g), and finally lattice formation. The cycle closes with ΔH_f = ΔH_sub + ½D(Cl–Cl) + IE₁(Na) – EA(Cl) + U(NaCl), where U is the lattice energy. The experimentally inaccessible lattice energy is computed from the other quantities; for s-block halides, U is large and negative because of the small ionic radii and high charge density. Down Group 1, U becomes less exothermic (larger ions), but this is partly offset by decreasing ionisation energy, which is why ΔH_f becomes more negative (more stable compound) down the group.

Polarisation and the Covalent Tendency

Fajans’ rules predict that a small cation with high charge polarises a large anion, giving covalent character. LiI, Li₂CO₃, and BeCl₂ are noticeably covalent — BeCl₂, for instance, sublimes and exists as a linear Cl–Be–Cl molecule in the gas phase but a polymeric chain in the solid. This same polarisation explains why Li₂CO₃ decomposes at ~1300 °C, Na₂CO₃ is stable to its melting point, while Group 2 carbonates require progressively higher temperatures to liberate CO₂. The order of thermal stability is therefore:

MgCO₃ < CaCO₃ < SrCO₃ < BaCO₃ (and Li₂CO₃ < Na₂CO₃ < K₂CO₃ in Group 1).

Amphoteric Character of BeO and Be(OH)₂

Unlike other s-block oxides, BeO reacts with both acids and strong bases:

  • BeO + 2HCl → BeCl₂ + H₂O (basic behaviour)
  • BeO + 2NaOH → Na₂BeO₂ + H₂O (acidic behaviour, forming beryllate)

This amphoterism is a diagonal-relationship fingerprint shared with Al₂O₃. MgO is predominantly basic but shows faint acidic behaviour only toward very strong bases.

Hydration Enthalpy and the Solubility Reversal

A salt dissolves readily when |ΔH_hydration| > |ΔH_lattice| and the entropy gain (TΔS) is favourable. For Group 2 hydroxides, lattice energy falls faster down the group than hydration enthalpy, so dissolution becomes easier → solubility increases down the group. For Group 2 sulphates, the very large SO₄²⁻ produces a small hydration gain on going from Ba²⁺ to Mg²⁺, while lattice energy remains large for MgSO₄; the net effect is that MgSO₄ is soluble, BaSO₄ is virtually insoluble, exploited in the qualitative test for Ba²⁺ and in medicine (barium meal).

Industrial Context and Quantitative Analysis

Beyond the Solvay tower, Na₂CO₃ is used in glass, detergents, and water softening, while Ca(OH)₂ (slaked lime) is critical in sugar refining and in scrubbing flue-gas SO₂. The Kjeldahl method (not s-block specific but often cross-referenced) uses NaOH to liberate NH₃ from ammonium salts. EDTA titration, however, is the workhorse for hardness: a standard NH₄Cl/NH₄OH buffer (pH ≈ 10) is used, and 1 mol of EDTA reacts with 1 mol of M²⁺.

Common Exam Traps

  • Reversing the hydroxide/sulphate solubility trends.
  • Writing the Solvay net equation as 2NaCl + CaCO₃ → Na₂CO₃ + CaCl₂, omitting the role of NH₃ as a recycled catalyst — UACE mark schemes penalise the omission of “with NH₃ recycled”.
  • Confusing lime water turning milky (Ca(OH)₂ + CO₂ → CaCO₃) with permanent milkiness that disappears in excess CO₂ due to Ca(HCO₃)₂ formation.
  • Stating that all Group 1/2 oxides are basic; BeO and partially MgO are exceptions.

Worked Example

A 200 cm³ water sample required 18.00 cm³ of 0.0100 mol dm⁻³ EDTA for total hardness. Moles of EDTA = 1.80 × 10⁻⁴ mol, which equals moles of Ca²⁺ (treated as CaCO₃ equivalent) = 1.80 × 10⁻⁴ mol. Mass of CaCO₃ equivalent = 1.80 × 10⁻⁴ × 100 = 0.0180 g in 200 cm³, i.e. 90 mg dm⁻³ CaCO₃ (the WHO acceptable limit is 500 mg dm⁻³).

Practice Prompts

  1. Explain, with equations, why the thermal stability of Group 2 carbonates increases down the group.
  2. Outline the Solvay process with a labelled flow diagram and state how ammonia is recovered.

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