Algebra
🟢 Lite — Quick Review (1h–1d)
Rapid summary for last-minute revision before your exam.
Quadratic Equation: $ax^2 + bx + c = 0$ with $a \neq 0$.
Quadratic Formula: $$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$
Discriminant $D = b^2 - 4ac$:
- $D > 0$: Two distinct real roots
- $D = 0$: Equal real roots
- $D < 0$: Complex conjugate roots
Sum and Product of Roots: If $\alpha, \beta$ are roots: $\alpha + \beta = -b/a$, $\alpha\beta = c/a$.
Binomial Theorem: $(a+b)^n = \sum_{k=0}^n \binom{n}{k} a^{n-k} b^k$.
Logarithm Rules:
- $\log_a (xy) = \log_a x + \log_a y$
- $\log_a (x/y) = \log_a x - \log_a y$
- $\log_a (x^k) = k \log_a x$
⚡ NDA Tip: When solving quadratic equations with parameters, identify cases where the parameter makes the equation degenerate (coefficient of $x^2$ becomes 0).
⚡ Common Mistake: $\log_a (x+y) \neq \log_a x + \log_a y$. Only product splits, not sum. Similarly $\log_a (x-y)$ is not defined in general.
🟡 Standard — Regular Study (2d–2mo)
For students who want genuine understanding.
Arithmetic Progression (AP): $a_n = a_1 + (n-1)d$. Sum $S_n = \frac{n}{2}(2a_1 + (n-1)d) = \frac{n(a_1+a_n)}{2}$.
Geometric Progression (GP): $a_n = a_1 \cdot r^{n-1}$. Sum $S_n = a_1 \frac{r^n-1}{r-1}$ for $r \neq 1$. Infinite sum $S_\infty = \frac{a_1}{1-r}$ if $|r| < 1$.
Harmonic Progression (HP): If $a, b, c$ are in HP, then $\frac{1}{a}, \frac{1}{b}, \frac{1}{c}$ are in AP. No formula for HP sum directly — convert to AP.
Permutation and Combination:
- $P(n,r) = \frac{n!}{(n-r)!}$ (arrangement)
- $C(n,r) = \binom{n}{r} = \frac{n!}{r!(n-r)!}$ (selection)
- $\binom{n}{r} = \binom{n}{n-r}$ (symmetry)
Matrices:
- $2 \times 2$ determinant: $\begin{vmatrix} a & b \ c & d \end{vmatrix} = ad - bc$
- Matrix multiplication: row of A times column of B
Complex Numbers: $i = \sqrt{-1}$, $i^2 = -1$. If $z = x + iy$, then $|z| = \sqrt{x^2+y^2}$ and $\bar{z} = x - iy$. $z^{-1} = \frac{\bar{z}}{|z|^2}$.
Worked Examples:
Example 1: If roots of $x^2 - px + q = 0$ are in ratio 3:4, find relation between $p$ and $q$.
Let roots be $3k$ and $4k$. Sum: $3k + 4k = 7k = p$ → $k = p/7$. Product: $3k \cdot 4k = 12k^2 = q$. So $12(p/7)^2 = q$ → $12p^2/49 = q$. Thus $q = \frac{12}{49}p^2$.
Example 2: Solve $\log_2(x+1) + \log_2(x-1) = 3$.
Using log rules: $\log_2[(x+1)(x-1)] = 3$ → $\log_2(x^2-1) = 3$. So $x^2 - 1 = 2^3 = 8$ → $x^2 = 9$ → $x = \pm 3$. Check domain: $x+1 > 0$ and $x-1 > 0$ gives $x > 1$. So $x = -3$ is extraneous (doesn’t satisfy $x > 1$). Thus $x = 3$.
Example 3: Find number of ways to arrange letters of “ARMY” and “ARRANGE”.
ARMY: 4 distinct letters, arrangements $= 4! = 24$. ARRANGE: A appears twice, R appears twice. Arrangements $= \frac{7!}{2! \cdot 2!} = \frac{5040}{4} = 1260$.
🔴 Extended — Deep Study (3mo+)
Comprehensive coverage for students on a longer study timeline.
De Moivre’s Theorem: $(\cos\theta + i\sin\theta)^n = \cos(n\theta) + i\sin(n\theta)$.
This allows finding powers and roots of complex numbers. $n$-th roots of unity: $z^k$ where $z = e^{2\pi i/n}$, $k = 0,1,\ldots,n-1$.
Binomial Theorem for Any Index: For real $n$: $(1+x)^n = 1 + nx + \frac{n(n-1)}{2!}x^2 + \cdots$. Converges for $|x| < 1$ when $n$ is not a positive integer.
Permutations with Repetitions:
- $n$ objects with $p$ alike of type 1, $q$ alike of type 2: $\frac{n!}{p!q!}$
- Arrange $n$ items into $r$ groups (allow empty groups): $r^n$
Determinant Properties:
- Rows can be added/subtracted without changing value
- Swapping rows changes sign
- Multiply row by constant $k$: determinant multiplied by $k$
- If two rows identical, determinant is 0
- Cofactor expansion along any row/column
Set Theory:
- $|A \cup B| = |A| + |B| - |A \cap B|$
- $|A \cup B \cup C| = |A| + |B| + |C| - |A \cap B| - |B \cap C| - |C \cap A| + |A \cap B \cap C|$
- $A \times B$ (Cartesian product): $|A \times B| = |A| \cdot |B|$
Advanced Problems:
Problem (NDA Pattern): Find sum of all 4-digit numbers formed using digits 1, 2, 3, 4 if repetition allowed.
Using digits 1, 2, 3, 4, each of 4 positions can be filled in 4 ways: $4^4 = 256$ numbers. Sum of digits in each position: Ones place: each digit appears equally often: $256/4 = 64$ times. Sum $= 64 \cdot (1+2+3+4) = 64 \cdot 10 = 640$. Similarly for tens, hundreds, thousands: each gives sum $640 \cdot 10^{position}$. Total sum $= 640(1 + 10 + 100 + 1000) = 640 \cdot 1111 = 711040$.
Problem: Find the complex cube roots of unity.
$z^3 = 1$ → $z^3 - 1 = 0$ → $(z-1)(z^2+z+1) = 0$. Roots: $z = 1$ and $z = \frac{-1 \pm i\sqrt{3}}{2}$. Note that the non-real roots are conjugates: if $\omega$ is one non-real root, $\omega^2$ is the other.
NDA Exam Pattern:
- NDA Mathematics has 120 questions, 300 marks
- Algebra questions are common (15-20 questions)
- Focus on solving equations and inequalities
- Permutations and combinations appear regularly
- Determinants and matrices (2x2, 3x3) are tested
- Complex numbers tested but usually basic operations
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