Number System
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Number System — Key Facts for NABE (Pakistan)
- Natural Numbers: 1, 2, 3, 4, … | Whole Numbers: 0, 1, 2, 3, …
- Integers: …-3, -2, -1, 0, 1, 2, 3, … | Rational: p/q where q ≠ 0
- Divisibility: Key rules — 2 (even), 3 (digit sum), 5 (ends 0/5), 9 (digit sum), 10 (ends 0)
- HCF × LCM = Product of two numbers (for any two positive integers)
- ⚡ Exam tip: Number of factors from prime factorization: if N = p^a × q^b, then factors = (a+1)(b+1)
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Number System — NABE (Pakistan) Study Guide
Classification of Numbers
Numbers
├── Natural Numbers: 1, 2, 3, ... (counting numbers)
├── Whole Numbers: 0, 1, 2, 3, ... (natural + zero)
├── Integers: ..., -3, -2, -1, 0, 1, 2, 3, ...
├── Even Numbers: Divisible by 2 (0, 2, 4, 6, ...)
├── Odd Numbers: Not divisible by 2 (1, 3, 5, 7, ...)
├── Prime Numbers: Divisible only by 1 and itself (2, 3, 5, 7, 11, ...)
├── Composite Numbers: Have other factors (4, 6, 8, 9, 10, ...)
└── Rational Numbers: Can be expressed as p/q where q ≠ 0
Divisibility Rules
| Divisor | Rule |
|---|---|
| 2 | Last digit is even (0, 2, 4, 6, 8) |
| 3 | Sum of digits is divisible by 3 |
| 4 | Last two digits form a number divisible by 4 |
| 5 | Last digit is 0 or 5 |
| 6 | Divisible by 2 AND 3 |
| 8 | Last three digits form a number divisible by 8 |
| 9 | Sum of digits is divisible by 9 |
| 10 | Last digit is 0 |
HCF and LCM
HCF (GCD): Highest Common Factor — largest number that divides both
LCM: Lowest Common Multiple — smallest number divisible by both
Key Formula: For any two positive integers a and b:
HCF(a, b) × LCM(a, b) = a × b
Example: Find HCF and LCM of 12 and 18
- 12 = 2² × 3
- 18 = 2 × 3²
- HCF = 2¹ × 3¹ = 6
- LCM = 2² × 3² = 36
- Check: 6 × 36 = 12 × 18 = 216 ✓
NABE Exam Pattern
Common question types:
- Divisibility and factors
- HCF and LCM calculations
- Prime factorization
- Number of factors and sum of factors
- Finding remainders
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Number System — Comprehensive NABE (Pakistan) Notes
Detailed Theory
1. Number Classification — Expanded
Natural Numbers (N): 1, 2, 3, 4, …
- Subset: Even (2, 4, 6, …), Odd (1, 3, 5, …)
Whole Numbers (W): 0, 1, 2, 3, …
Integers (Z): All whole numbers and their negatives
- Z⁺ = Positive integers = {1, 2, 3, …}
- Z⁻ = Negative integers = {…-3, -2, -1}
- Z₀ = {…-2, -1, 0, 1, 2, …}
Rational Numbers (Q): p/q where p, q are integers, q ≠ 0
- Includes all fractions and integers
- Decimal expansion: terminating or repeating
Irrational Numbers: Cannot be expressed as p/q
- Examples: √2, π, e, √3
- Decimal expansion: non-terminating, non-repeating
Real Numbers (R): Rational + Irrational
2. Prime Numbers — Complete Analysis
Definition: A prime number has exactly two distinct factors: 1 and itself.
First 20 Primes: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71
Properties of Prime Numbers:
- 2 is the only even prime
- All primes greater than 3 are of the form 6k ± 1
- There are infinitely many primes (Euclid’s proof)
- No formula generates all primes
Prime Testing:
- To check if n is prime, test divisibility by primes ≤ √n
- Example: Is 97 prime? Check primes ≤ √97 ≈ 9.8 → 2, 3, 5, 7
- 97 not divisible by any → 97 is prime
Sieve of Eratosthenes: Method to find all primes up to n
- List numbers 2 to n
- Mark 2, cross out all multiples of 2
- Next unmarked number is prime, cross out its multiples
- Repeat until √n
3. Co-Prime Numbers
Definition: Two numbers are co-prime if their HCF = 1
- Examples: (8, 15), (7, 9), (14, 15)
- Note: Co-prime numbers need not be primes individually
Properties:
- If a and b are co-prime: LCM(a, b) = a × b
- φ(n) = count of numbers less than n and co-prime to n (Euler’s totient)
4. HCF and LCM — Methods
Prime Factorization Method:
HCF: Take MINIMUM powers of common primes
LCM: Take MAXIMUM powers of all primes
Example: Find HCF and LCM of 60, 72, and 120
- 60 = 2² × 3¹ × 5¹
- 72 = 2³ × 3²
- 120 = 2³ × 3¹ × 5¹
- HCF = 2² × 3¹ = 12
- LCM = 2³ × 3² × 5¹ = 360
Division Method:
- LCM: Divide successively by primes until all quotients are 1
- HCF: Divide larger by smaller, then remainder by previous divisor until remainder = 0
5. Number of Factors (Divisors)
If N = p^a × q^b × r^c, then:
Number of Factors (d) = (a+1)(b+1)(c+1)
Sum of Factors (σ) = [(p^(a+1)-1)/(p-1)] × [(q^(b+1)-1)/(q-1)] × ...
Example: Find number of factors of 180
- 180 = 2² × 3² × 5¹
- d(180) = (2+1)(2+1)(1+1) = 3 × 3 × 2 = 18 factors
Perfect Numbers: Sum of proper divisors equals the number
- Example: 6 (1+2+3=6), 28 (1+2+4+7+14=28)
6. Factorial Notation
n! = 1 × 2 × 3 × … × n
Highest Power of Prime p in n!:
v_p(n!) = ⌊n/p⌋ + ⌊n/p²⌋ + ⌊n/p³⌋ + ...
Example: Highest power of 3 in 10!
- v₃(10!) = ⌊10/3⌋ + ⌊10/9⌋ = 3 + 1 = 4
- 10! = 3628800, which is divisible by 3⁴ = 81 but not 3⁵ = 243
7. Cyclicity and Last Digits
Last digit patterns cycle:
- 2^1=2, 2^2=4, 2^3=8, 2^4=6, 2^5=2… cycle: 2,4,8,6
- 3^1=3, 3^2=9, 3^3=7, 3^4=1, 3^5=3… cycle: 3,9,7,1
- 7^1=7, 7^2=9, 7^3=3, 7^4=1, 7^5=7… cycle: 7,9,3,1
To find last digit of a^b: Find remainder of b divided by cycle length, use that power.
8. Congruences (Basics)
Definition: a ≡ b (mod m) means m divides (a-b)
Properties:
- a ≡ a (mod m) [reflexive]
- If a ≡ b, then b ≡ a (mod m) [symmetric]
- If a ≡ b and b ≡ c, then a ≡ c (mod m) [transitive]
Application: Finding remainders
- Example: Find remainder when 2^100 is divided by 3
- 2 ≡ -1 (mod 3)
- 2^100 ≡ (-1)^100 ≡ 1 (mod 3)
- Remainder = 1
9. Arithmetic Progression (Related)
If numbers form an AP with common difference d:
- Sum of n terms: n/2 × (first + last) = n/2 × [2a + (n-1)d]
- Sum of first n natural numbers: n(n+1)/2
10. Common Mistakes to Avoid
- 1 is not prime: 1 has only one factor, primes need exactly two
- HCF × LCM: Only applies to two numbers (not three)
- Divisibility check: Test all applicable rules
- Proper factors: Exclude the number itself
- Negative numbers: Be careful with divisibility rules
Practice Questions for NABE
- Find the HCF and LCM of 72, 120, and 156 using prime factorization.
- How many factors does 360 have? List them.
- Find the highest power of 5 in 100!
- If the LCM of two numbers is 180 and their HCF is 15, and one number is 45, find the other.
- Prove that the product of three consecutive integers is always divisible by 6.
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