Chemical Equilibrium
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Chemical Equilibrium — Key Facts for MDCAT
Key Definitions:
- Reversible reaction: Can proceed in both forward and backward directions
- Equilibrium: Rate of forward reaction = Rate of reverse reaction; concentrations of reactants and products remain CONSTANT (not equal) with time
- Dynamic equilibrium: Both forward and reverse reactions continue indefinitely; macroscopic properties are static but microscopic processes continue
Law of Mass Action: For a general reaction: $aA + bB \rightleftharpoons cC + dD$ $$K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b} \text{ (at equilibrium)}$$ Where $[A]$, $[B]$, $[C]$, $[D]$ are molar concentrations at equilibrium.
Equilibrium Constant ($K_c$):
- $K_c >> 1$ (typically > 10³): Products are favoured; reaction lies to the right
- $K_c << 1$ (typically < 10⁻³): Reactants are favoured; reaction lies to the left
- $K_c ≈ 1$: Neither reactants nor products are strongly favoured
For gaseous reactions, use partial pressures: $$K_p = \frac{P_C^c \cdot P_D^d}{P_A^a \cdot P_B^b}$$ Relationship: $K_p = K_c(RT)^{\Delta n}$ where $\Delta n = (c+d) - (a+b)$
⚡ Exam tip: Only gaseous species and aqueous species appear in the $K$ expression. Pure solids and pure liquids are NOT included (their activities = 1). For the reaction $CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)$, $K_p = P_{CO_2}$ only. MDCAT commonly tests this distinction.
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Chemical Equilibrium — Complete Study Guide
Le Chatelier’s Principle: If a system at equilibrium is subjected to a change in concentration, temperature, pressure, or volume, the system will shift to partially counteract the change and establish a new equilibrium.
| Change | Effect |
|---|---|
| Increase [reactants] | Shift right (towards products) |
| Decrease [reactants] | Shift left (towards reactants) |
| Increase temperature (endothermic) | Shift right |
| Increase temperature (exothermic) | Shift left |
| Increase pressure (gas reactions) | Shift towards fewer moles of gas |
| Decrease pressure | Shift towards more moles of gas |
| Catalyst added | No shift — only speeds up attainment of equilibrium |
Effect of Pressure on Equilibrium: For $N_2O_4(g) \rightleftharpoons 2NO_2(g)$:
- Reactant side: 1 mole gas; Product side: 2 moles gas
- Increasing pressure → shift LEFT (towards fewer gas moles)
- The equilibrium constant $K$ itself does NOT change with pressure — only the position shifts
Relation between $K$ and $K_{sp}$ (Solubility Product): For the dissolution equilibrium: $MX(s) \rightleftharpoons M^{n+}(aq) + X^{n-}(aq)$ $$K_{sp} = [M^{n+}][X^{n-}]$$ Precipitation occurs when the ion product (IP) > $K_{sp}$.
Reaction Quotient ($Q$): $$Q = \frac{[C]^c[D]^d}{[A]^a[B]^b}$$
- If $Q < K$: Reaction shifts right (towards products) to reach equilibrium
- If $Q > K$: Reaction shifts left (towards reactants) to reach equilibrium
- If $Q = K$: System is at equilibrium
Important Equilibria in Industry:
-
Haber process: $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$, $\Delta H = -92$ kJ/mol (exothermic)
- Low temperature favours products BUT slow at low T → compromise at ~400–500°C with catalyst
- High pressure favours products (4 → 2 moles) → high pressure (~200 atm)
- Iron catalyst speeds up without affecting equilibrium position
-
Contact process: $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$, $\Delta H = -197$ kJ/mol
- V$_2$O$_5$ catalyst for sulfuric acid manufacture
⚡ Common mistakes: Thinking equilibrium means equal concentrations (wrong — only rates are equal). Adding a catalyst and expecting the equilibrium position to shift (it doesn’t — only speeds up reaching equilibrium). Confusing $K_c$ units with $K_p$ — $K_c$ has units of (mol/L)$^{\Delta n}$, $K_p$ has units of atm$^{\Delta n}$.
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Chemical Equilibrium — Advanced Notes
Thermodynamic Derivation of Equilibrium Constant: $$\Delta G = \Delta G^\circ + RT\ln Q$$ At equilibrium: $\Delta G = 0$, $Q = K$ $$\therefore \Delta G^\circ = -RT\ln K$$ Also: $\Delta G^\circ = \Delta H^\circ - T\Delta S^\circ$
This links thermodynamics (Gibbs energy) with the equilibrium constant. A negative $\Delta G^\circ$ means $K > 1$.
Van’t Hoff Equation (Temperature Dependence of $K$): $$\frac{d\ln K}{dT} = \frac{\Delta H^\circ}{RT^2}$$ Integrating: $\ln\frac{K_2}{K_1} = \frac{\Delta H^\circ}{R}\left(\frac{1}{T_1} - \frac{1}{T_2}\right)$
- For exothermic reactions ($\Delta H < 0$): Increasing $T$ → $K$ decreases
- For endothermic reactions ($\Delta H > 0$): Increasing $T$ → $K$ increases
Degree of Dissociation ($\alpha$): For $PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$: Let initial moles of $PCl_5 = 1$, degree of dissociation = $\alpha$ At equilibrium: $[PCl_5] = (1-\alpha)V$, $[PCl_3] = \alpha/V$, $[Cl_2] = \alpha/V$ $$K_p = \frac{\alpha^2 P}{(1-\alpha)-\alpha^2} \text{ (for 1 atm initial)}$$
Simultaneous/Homogeneous vs Heterogeneous Equilibrium:
- Homogeneous: All species in same phase (usually gas)
- Heterogeneous: Species in different phases (e.g., solid + gas)
- For $CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)$: $K_p = P_{CO_2}$
- Activities of pure solids and liquids = 1, so they don’t appear in $K$ expression
Buffer Solutions and Equilibrium: The pH of a buffer containing a weak acid HA and its salt NaA: $$K_a = \frac{[H^+][A^-]}{[HA]} \Rightarrow [H^+] = K_a \frac{[HA]}{[A^-]}$$ Henderson-Hasselbalch: $pH = pK_a + \log\frac{[\text{salt}]}{[\text{acid}]}$
Salt Hydrolysis and $K_h$: For salt of weak acid and strong base (e.g., CH$_3$COONa): $$K_h = \frac{K_w}{K_a}$$ Degree of hydrolysis $h = \sqrt{\frac{K_h}{C}}$ where $C$ is concentration.
Common Ion Effect: The suppression of dissociation of a weak electrolyte by adding a strong electrolyte containing a common ion. Example: Adding NaOH (Na⁺, OH⁻) to NH₃/NH₄⁺ buffer shifts the equilibrium.
MDCAT Question Patterns: MDCAT Pakistan chemical equilibrium questions frequently test: (1) writing $K_c$ and $K_p$ expressions correctly (excluding solids/liquids), (2) Le Chatelier’s principle applications to Haber process, (3) calculating equilibrium concentrations, (4) relationship between $K_p$ and $K_c$, (5) using $Q$ to predict direction of shift, (6) van’t Hoff equation for temperature effects. 2–3 questions per paper. Le Chatelier’s principle in industrial contexts (ammonia synthesis) is very common.
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📐 Diagram Reference
Clear scientific diagram of Chemical Equilibrium with atom labels, molecular structure, reaction arrows, white background, color-coded bonds and groups, exam textbook style
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