Skip to main content
Chemistry 3% exam weight

Haloalkanes

Part of the JEE Main study roadmap. Chemistry topic chem-021 of Chemistry.

By Last updated 3% exam weight

Haloalkanes

🟢 Lite — Quick Review (1h–1d)

Rapid summary for last-minute revision before your exam.

Haloalkanes (alkyl halides) are saturated aliphatic compounds in which one or more hydrogen atoms of an alkane are replaced by halogen atoms (F, Cl, Br, I). Mono-haloalkanes follow the general formula C_nH_(2n+1)X, where X is the halogen. They are classified by the carbon bearing X as primary (1°), secondary (2°), or tertiary (3°), and by hybridization as sp³ (alkyl), sp² (vinyl, allyl, aryl), or sp types.

Must-know reactivity order: C–X bond strength is C–F > C–Cl > C–Br > C–I, so reactivity is the reverse: RI > RBr > RCl > RF. Leaving-group ability: I⁻ > Br⁻ > Cl⁻ > F⁻.

SN2 vs SN1 at a glance: SN2 is bimolecular, rate = k[Substrate][Nucleophile], and prefers 1° > 2° > 3° (steric hindrance). SN1 is unimolecular, rate = k[Substrate], and prefers 3° > 2° > 1° (carbocation stability). JEE pointer: elimination (E1/E2) competes with substitution; bulky base (t-BuOK) gives Hofmann product (less substituted alkene), small base (EtONa) gives Zaitsev product.


🟡 Standard — Regular Study (2d–2mo)

Standard content for students with a few days to months.

Classification and Bonding

The halogen in a haloalkane is bonded to a carbon framework. Counting the number of carbons attached to the C–X carbon gives 1°, 2°, or 3° classification. Hybridization matters: sp³ alkyl halides (saturated) are reactive, while sp² vinyl (C=C–X) and sp² aryl (Ar–X) halides are notably unreactive toward SN1/SN2 because the C–X bond has partial double-bond character (especially in aryl halides, where lone-pair donation from halogen into the ring strengthens the bond) and the carbon is geometrically inaccessible.

Boiling Point Trend

For a fixed alkyl group, boiling point follows RI > RBr > RCl > RF because London dispersion forces grow with the size and polarizability of X. For a fixed halogen, boiling point increases with chain length and branching reduces it.

Nucleophilic Substitution

SN2 is a single-step, concerted, back-side attack. The rate depends on both substrate and nucleophile: Rate_SN2 = k[Substrate][Nucleophile]. Reactivity order: CH₃X > 1° > 2° > 3° (steric blocking). It proceeds with Walden inversion of configuration. Polar aprotic solvents (DMSO, DMF, acetone) accelerate SN2 by leaving the nucleophile “naked” and reactive.

SN1 is a two-step mechanism via a planar carbocation. Rate_SN1 = k[Substrate]. Reactivity: 3° > 2° > 1° > CH₃ (carbocation stability: 3° > 2° > 1° > methyl, plus hyperconjugation and +I effects). The intermediate planar cation gives a racemic mixture if the carbon was a stereocenter. Polar protic solvents (water, alcohol) stabilize the carbocation and the leaving anion, favoring SN1.

Allylic and benzylic halides are special: allyl and benzyl cations are resonance-stabilized, giving high SN1 reactivity; allyl systems also undergo SN1’ (allylic rearrangement).

Elimination (β-Hydrogen Removal)

E1 (carbocation, unimolecular) competes with SN1; E2 (concerted, bimolecular) competes with SN2. Zaitsev’s rule: the more substituted alkene is the major product with a small base. With a bulky base like potassium tert-butoxide, the less substituted Hofmann alkene dominates.

Preparation Snapshot

MethodReactionNotes
From alcohol + HXR–OH + HX → R–X + H₂O3°/2° via SN1; 1° needs ZnCl₂ (Lucas)
PCl₃ / PCl₅ / SOCl₂R–OH → R–ClSOCl₂ gives gaseous by-products, easy work-up
Alkene + HXMarkovnikov additionPeroxides give anti-Markovnikov (HBr only)
Free-radical halogenationR–H + X₂ → R–X (with light/heat)Poor selectivity, mixture of products
FinkelsteinR–X + NaI (acetone) → R–I + NaX↓Equilibrium driven by NaCl/NaBr precipitation
SwartsR–Cl/Br + AgF → R–FUsed to make alkyl fluorides
HunsdieckerRCOOAg + Br₂ → R–Br + CO₂ + AgBrOne-carbon degradation of silver carboxylate

Exam-Style Patterns

JEE Main frequently tests: (1) rate-law identification from kinetic data, (2) stereochemistry (inversion vs retention vs racemisation), (3) major product prediction in substitution/elimination competitions, and (4) Grignard-based carbon–carbon bond formation.


🔴 Extended — Deep Study (3mo+)

Comprehensive coverage for students on a longer study timeline.

C–X Bond Mechanics

Bond length shortens and bond dissociation enthalpy rises from C–I to C–F because of poorer orbital overlap with heavier halogens and stronger coulombic attraction with fluorine. The percent s-character governs C–X bond length: sp³ 25%, sp² 33.3%, sp 50% — hence vinyl and aryl C–X bonds are shorter and stronger, explaining their inertness. A C–Cl bond in chlorobenzene has partial double-bond character due to resonance, raising its bond energy to roughly 96 kcal/mol, comparable to a C–C bond, so nucleophilic attack is suppressed.

Solvent and Nucleophile Effects

Polar protic solvents (H₂O, ROH, HCOOH) hydrogen-bond to anionic nucleophiles, lowering nucleophilicity but solvating the carbocation intermediate — ideal for SN1. Polar aprotic solvents (DMSO, DMF, acetone, acetonitrile) expose the anion, dramatically increasing SN2 rates; for example, the SN2 reaction of CH₃Br with I⁻ is roughly 1000× faster in DMF than in methanol. Nucleophilicity in protic media follows I⁻ > Br⁻ > Cl⁻ > F⁻ (polarizability); in aprotic media it tracks basicity: F⁻ > Cl⁻ > Br⁻ > I⁻.

Eliminating the Confusion: SN1/SN2/E1/E2 Decision Tree

Check the substrate: 3° favors SN1/E1 (unless strong bulky base → E2), 1°/CH₃ favors SN2, 2° is genuinely competitive and the deciding factors are solvent (aprotic → SN2) and nucleophile/base strength. Temperature higher than ~50 °C shifts equilibrium toward elimination.

Grignard Reagents and Wurtz Coupling

RMgX reagents are made in dry ether (or THF) and act as both strong bases and carbanion equivalents. They react with aldehydes, ketones, esters, and CO₂ to form C–C bonds, producing primary, secondary, or tertiary alcohols depending on the carbonyl partner. The Wurtz reaction (2 R–X + 2 Na → R–R + 2 NaX) works best for symmetrical alkanes from CH₃X and 1° halides; 3° halides give mainly elimination. Corey–House synthesis (R–X + Li → R–Li; R–Li + R’–X → R–R’) overcomes this limitation for unsymmetrical coupling.

Common Pitfalls in JEE

  1. Writing the rate law for SN1 as bimolecular (it’s unimolecular).
  2. Predicting inversion of configuration in SN1 (it’s racemisation because the carbocation is planar).
  3. Assuming vinyl chloride behaves like ethyl chloride in elimination — it doesn’t, because of sp² carbon geometry.
  4. Forgetting that Finkelstein requires NaI in acetone (not aqueous), and Swarts uses heavy-metal fluorides like Hg₂F₂ or AgF.
  5. Mixing up Hofmann (less substituted, bulky base) with Zaitsev (more substituted, small base).

Practice Prompts

  1. Identify the major product and mechanism when (R)-2-bromobutane reacts with NaOH in (a) aqueous ethanol and (b) dry acetone. Justify with rate law and stereochemistry.
  2. Rank the following by SN1 reactivity and explain using carbocation stability: t-butyl bromide, isopropyl bromide, n-propyl bromide, allyl bromide, benzyl bromide.

Content adapted based on your selected roadmap duration. Switch tiers using the selector above.

Sources & verification