EMI (Electromagnetic Induction)
🟢 Lite — Quick Review (1h–1d)
Rapid summary for last-minute revision before your exam.
EMI and AC — Key Facts
Faraday’s Law of Electromagnetic Induction:
Induced EMF equals the negative rate of change of magnetic flux: $$\varepsilon = -\frac{d\Phi}{dt}$$
The minus sign indicates Lenz’s Law — induced current opposes the change in flux.
Magnetic Flux: $$\Phi = \vec{B} \cdot \vec{A} = BA\cos\theta$$
Unit: Weber (Wb), where 1 Wb = 1 T·m²
Lenz’s Law: The direction of induced current is such that it opposes the change that produced it.
⚡ JEE Exam Tip: Always apply Lenz’s Law before determining current direction. If flux is increasing, induced B is opposite to external B. If flux is decreasing, induced B is in same direction as external B.
🟡 Standard — Regular Study (2d–2mo)
For students who want genuine understanding…
Motional EMF:
When a conductor of length ℓ moves with velocity v perpendicular to magnetic field B: $$\varepsilon = B\ell v$$
General case (at angle θ to perpendicular): $\varepsilon = B\ell v\sin\theta$
This is equivalent to the rate of change of flux through the moving loop.
Self-Induction:
When current in a coil changes, changing flux through the coil induces EMF in itself: $$\varepsilon = -L\frac{dI}{dt}$$
Self-inductance L depends on coil geometry:
- Solenoid: $L = \mu_0 n^2 A \ell$ (n = turns per unit length, A = area, ℓ = length)
- Toroid: $L = \mu_0 n^2 \cdot 2\pi r \cdot A$
Energy stored in inductor: $$U = \frac{1}{2}LI^2$$
Mutual Induction:
When current in one coil changes, it induces EMF in a nearby coil: $$\varepsilon_2 = -M\frac{dI_1}{dt}$$
Mutual inductance M depends on geometry of both coils and their separation.
For two coils with N₁ and N₂ turns: $M = k\sqrt{L_1 L_2}$ where k = coefficient of coupling (0 ≤ k ≤ 1)
⚡ JEE Exam Tip: If two inductors with self-inductances L₁ and L₂ have mutual inductance M, the equivalent inductance depends on whether they’re connected in series (with or without coupling) or parallel. For series with aiding coupling: $L_{eq} = L_1 + L_2 + 2M$.
🔴 Extended — Deep Study (3mo+)
Comprehensive coverage for students on a longer study timeline.
Induced Electric Field:
Changing magnetic field produces a circulating (non-conservative) electric field: $$\oint \vec{E} \cdot d\vec{l} = -\frac{d\Phi_B}{dt}$$
This is Faraday’s Law in integral form — fundamentally different from electrostatics where $\oint \vec{E} \cdot d\vec{l} = 0$.
AC Generator:
Converts mechanical energy to electrical energy using electromagnetic induction.
For N-turn coil rotating at angular velocity ω in uniform B: $$\varepsilon = \varepsilon_0 \sin(\omega t)$$
where $\varepsilon_0 = NBA\omega$ (peak emf)
A = area of coil, B = magnetic field strength
Frequency: $f = \omega/2\pi$ Hz
Transformer:
Works on mutual induction principle.
Ideal transformer (100% efficient): $$\frac{V_s}{V_p} = \frac{N_s}{N_p} = \frac{I_p}{I_s}$$
In practice:
- Copper losses (I²R in windings)
- Iron losses (hysteresis + eddy currents in core)
- Flux leakage
Efficiency: $\eta = \frac{P_{out}}{P_{in}} \approx 90-99%$ for large transformers
LR Circuit:
When switch is closed: $$I = \frac{\varepsilon}{R}(1 - e^{-t/\tau}) \quad \text{where } \tau = L/R$$
Time constant τ = L/R (time to reach 63% of final current)
LC Oscillations:
Without resistance, energy oscillates between capacitor and inductor: $$\omega_0 = \frac{1}{\sqrt{LC}}$$
Analogy with spring-mass system:
- Capacitor ↔ spring (stores potential energy)
- Inductor ↔ mass (stores kinetic energy)
Total energy: $U = \frac{1}{2}\frac{Q_0^2}{C} = \frac{1}{2}LI_0^2$ (conserved)
Eddy Currents:
Induced currents in bulk conductors when exposed to changing magnetic fields.
Applications:
- Electromagnetic braking
- Induction heating
- Eddy current damping
To minimise eddy currents: use laminated cores (thin insulated sheets), slots, or use insulators.
⚡ JEE Advanced 2023 Analysis: AC generators, transformers, and LC oscillations appeared in recent papers. For AC generator, average power output over complete cycle is zero unless load is connected — the mechanical power input equals electrical power delivered to load.
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