Thermochemistry and Energetics
🟢 Lite — Quick Review (1h–1d)
Rapid summary for last-minute revision before your exam.
Thermochemistry and Energetics — Key Facts First law of thermodynamics: $\Delta U = q + w$; energy is conserved, not created or destroyed Enthalpy change $\Delta H = \Delta U + P\Delta V$; for reactions at constant pressure Hess’s law: $\Delta H_{rxn} = \sum \Delta H_f°(products) - \sum \Delta H_f°(reactants)$ Standard enthalpy of formation $\Delta H_f°$: enthalpy change when 1 mole forms from elements in standard states ⚡ Exam tip: Bond dissociation energy is always positive (endothermic to break bond); bond formation is always negative (exothermic)
🟡 Standard — Regular Study (2d–2mo)
Standard content for students with a few days to months.
Thermochemistry and Energetics — JAMB Chemistry Study Guide
Types of enthalpy:
- $\Delta H_f°$: standard enthalpy of formation (elements → compound)
- $\Delta H_c°$: standard enthalpy of combustion (compound + O₂ → CO₂ + H₂O)
- $\Delta H_{diss}$: bond dissociation energy (breaking bonds)
- $\Delta H_{solution}$: enthalpy of solution
- $\Delta H_{atomisation}$: solid → gaseous atoms
Calorimetry: Heat $q = mc\Delta T$ where $m$ = mass, $c$ = specific heat capacity, $\Delta T$ = temperature change. For constant pressure calorimetry (coffee cup): $q_{rxn} = -q_{solution}$ For constant volume calorimetry (bomb calorimeter): $q_{rxn} = -\Delta U$ (no work done, so $\Delta U = q_v$)
Born-Haber cycle: Lattice energy = energy required to separate 1 mole of ionic solid into gaseous ions. $\Delta H_f° = \Delta H_{atomisation} + IE_1 + IE_2 + … + EA + U$ (with signs appropriate) Used to calculate lattice energy from measurable quantities.
Average bond enthalpy: Average energy to break a bond (per mole); can estimate $\Delta H_{rxn}$: $$\Delta H_{rxn} = \sum \Delta H_{bonds\ broken} - \sum \Delta H_{bonds\ formed}$$
Common student mistakes: Confusing $\Delta H$ and $\Delta U$ (for gases, $\Delta H = \Delta U + \Delta n_g \cdot RT$); forgetting signs for endothermic (+ΔH) vs exothermic (-ΔH); not using proper state symbols.
🔴 Extended — Deep Study (3mo+)
Comprehensive coverage for students on a longer study timeline.
Thermochemistry and Energetics — Comprehensive Chemistry Notes
Born-Haber cycle for NaCl: $\Delta H_f°(NaCl) = \Delta H_{sub}(Na) + IE_1(Na) + \frac{1}{2}\Delta H_{diss}(Cl_2) + EA(Cl) + U$ Where:
- $\Delta H_{sub} = 107$ kJ/mol (Na solid → Na gas)
- $IE_1 = 496$ kJ/mol (Na → Na⁺ + e⁻)
- $\frac{1}{2}\Delta H_{diss} = \frac{1}{2}(243) = 122$ kJ/mol ($Cl_2 \rightarrow 2Cl$)
- $EA = -349$ kJ/mol ($Cl + e^- \rightarrow Cl^-$)
- $U = ?$ (lattice energy, calculated to be -788 kJ/mol) $\Delta H_f° = 107 + 496 + 122 - 349 - 788 = -412$ kJ/mol (observed: -411 kJ/mol)
Entropy: $\Delta S° = \sum S°(products) - \sum S°(reactants)$ Second law: $\Delta S_{universe} = \Delta S_{system} + \Delta S_{surroundings} > 0$ for spontaneous process. $\Delta S_{surroundings} = -\Delta H_{system}/T$ (at constant pressure and temperature)
Gibbs free energy: $\Delta G° = \Delta H° - T\Delta S°$
- $\Delta G° < 0$: spontaneous
- $\Delta G° = 0$: at equilibrium
- $\Delta G° > 0$: non-spontaneous
At equilibrium: $\Delta G = 0$, so $\Delta H = T\Delta S$ Also: $\Delta G° = -RT\ln K$ where $K$ is equilibrium constant.
Thermodynamic vs kinetic control: A reaction may be thermodynamically favoured ($\Delta G < 0$) but kinetically slow ($E_a$ high). A catalyst affects kinetics but not thermodynamics.
JAMB exam patterns:
- 2023 JAMB: Calculate $\Delta H$ for reaction $N_2 + 3H_2 \rightarrow 2NH_3$ given bond enthalpies
- 2022 JAMB: State Hess’s law and calculate $\Delta H°$ using standard enthalpies of formation
- 2021 JAMB: Predict whether $\Delta S$ is positive or negative for the reaction $CaCO_3(s) \rightarrow CaO(s) + CO_2(g)$
- 2020 JAMB: Why does spontaneity not depend only on enthalpy?
Bond dissociation energies (kJ/mol):
| Bond | Energy | Bond | Energy |
|---|---|---|---|
| C-H | 413 | H-H | 436 |
| C-C | 347 | O=O | 496 |
| C=O | 799 | O-H | 463 |
| C≡O | 1072 | N≡N | 945 |
| C-Cl | 339 | Cl-Cl | 243 |
📊 JAMB Exam Essentials
| Detail | Value |
|---|---|
| Questions | 180 MCQs (UTME) |
| Subjects | 4 subjects (language + 3 for course) |
| Time | 2 hours |
| Marking | +1 per correct answer |
| Score | 400 max (used for university admission) |
| Registration | January – February each year |
🎯 High-Yield Topics for JAMB
- Use of English (Grammar + Comprehension) — 60 marks
- Biology for Science students — 40 marks
- Chemistry (Organic + Physical) — 40 marks
- Physics (Mechanics + Optics) — 35 marks
- Mathematics (Algebra + Geometry) — 40 marks
📝 Previous Year Question Patterns
- Q: “The process of photosynthesis requires…” [2024 Biology]
- Q: “The electronic configuration of Fe is…” [2024 Chemistry]
- Q: “Find the value of x if 2x + 5 = 15…” [2024 Mathematics]
💡 Pro Tips
- Use of English carries the most weight — master grammar rules and comprehension strategies
- JAMB syllabus is your Bible — questions come directly from it. Download and use it.
- Past questions are highly predictive — repeat patterns appear every year
- For Science students, Biology and Chemistry are high-scoring if you study NCERT-level content
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📐 Diagram Reference
Clear scientific diagram of Thermochemistry and Energetics with atom labels, molecular structure, reaction arrows, white background, color-coded bonds and groups, exam textbook style
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