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Quantitative Aptitude 2% exam weight

Simplification & BODMAS

Part of the CUET UG study roadmap. Quantitative Aptitude topic cuet-qa-002 of Quantitative Aptitude.

By Last updated 2% exam weight

Simplification & BODMAS

🟢 Lite

Key Formula/Rule

BODMAS Order: Brackets → Orders (powers/roots) → Division → Multiplication → Addition → Subtraction. Every operation in an expression follows this exact hierarchy — do the highest-ranked operation first, then work down.

Memory Trick

“BODMAS” — sing it like a cheer or use the mnemonic “Big Owls Drive My Auto Safely”. Each letter is a stage: Brackets (all types: (), {}, []), then Orders (squares, cubes, roots), then Division and Multiplication (left to right, NOT D before M), then Addition and Subtraction (left to right). When two ops have the same rank, go left to right.

1-Sentence Summary

BODMAS is the rule that tells you which mathematical operation to perform first in a multi-operation expression — brackets always resolve first, and division/multiplication are at the same rank (as are addition/subtraction).

30-Second Example

Q: Simplify 3 + 6 × (5 − 2)² ÷ √16 A: 16.5 — (i) Brackets: (5−2)=3 → 3 + 6 × 3² ÷ √16. (ii) Orders: 3²=9, √16=4 → 3 + 6 × 9 ÷ 4. (iii) D/M left to right: 6×9=54, 54÷4=13.5 → 3 + 13.5. (iv) A/S: 3 + 13.5 = 16.5.

Must Remember

  • Different brackets resolve in order: parentheses () → braces {} → brackets [] — treat innermost first
  • Division and multiplication have equal priority — whichever appears first (leftmost) gets done first, reading left to right
  • Addition and subtraction have equal priority — left to right
  • Powers before multiply/divide — 2³ × 4 means (8 × 4) = 32, not (2³ × 4)
  • Negative numbers: −(−3) = +3; −3 × (−2) = +6; always watch the signs carefully
  • Fraction bars act like brackets: (a+b)/(c−d) means calculate numerator and denominator first

Exam Tips for CUET

  • CUET frequently asks you to identify the WRONG step in a BODMAS evaluation — read the options carefully and check if they’re applying the correct order.
  • When an expression has no brackets, work through BODMAS in order: check for Orders first (no ² or √ here), then scan for D/M, then A/S.
  • Common trap: Students often do multiplication before division because M comes before D in BODMAS, but they have equal priority — go left to right.
  • If a fraction has a bracket-free numerator with mixed operations, still apply BODMAS to the top and bottom before dividing.

Common Pitfalls

  • Confusing left-right priority for D/M and A/S → 12 ÷ 4 × 3 = (12÷4)×3 = 9, NOT 12 ÷ (4×3) = 1. The leftmost division resolves first.
  • Forgetting that brackets can be nested: 2 × [3 + {4 × (5 − 1)}] — start from the innermost parentheses: (5−1)=4, then {4×4}=16, then [3+16]=19, then 2×19=38.
  • Missing a bracket type — all three bracket types can appear together. The resolving order is: innermost ( ) first, then { }, then [ ].
  • Misapplying distributive property: 5 × (2+3) ≠ 5×2 + 3 — it equals 5×2 + 5×3 = 25. The multiplication distributes over everything inside the brackets.

🟡 Standard

Concept

BODMAS is the rule that resolves ambiguity in mathematical expressions. Without it, “3 + 4 × 2” could mean 14 (left to right) or 11 (multiply first). BODMAS is the agreed convention: Brackets first, then Orders (squares, cubes, roots), then Division and Multiplication (left to right, whichever comes first), then Addition and Subtraction (left to right).

Brackets come in three flavours that nest inside each other:

  • Parentheses ( ) — the innermost
  • Braces { } — the middle layer
  • Square brackets [ ] — the outermost layer

When all three appear, solve from the inside out. For {2 + [3 × (4 + 5)]}: first the parentheses (4+5=9), then braces give {2 + [3 × 9]} = {2 + 27} = 29. Three layers, three steps.

Division and Multiplication are equal in priority — do whichever appears first as you read left to right. Same for Addition and Subtraction. A common mistake is treating DM as one block and AS as one block, then doing all M before all D. Wrong! 8 ÷ 4 × 2 = 4 (left to right), not 8 ÷ 8 = 1.

Key Formulas

FormulaUse
a ÷ b × c = (a ÷ b) × cLeft-to-right for DM
a − b + c = (a − b) + cLeft-to-right for AS
(a + b)² = a² + 2ab + b²Special expansion
√(a × b) = √a × √bRoot distributivity
a × (b + c) = a×b + a×cDistributive law

Worked Example

Q: Simplify: 48 ÷ {5 − [3 × (2 + 1)]}

Step 1: Innermost brackets → (2 + 1) = 3 Step 2: Now [3 × 3] = 9 Step 3: Now {5 − 9} = −4 Step 4: 48 ÷ (−4) = −12

Answer: −12

Common Errors

  • Doing multiplication before division (or addition before subtraction) → remember they’re equal priority, go left to right
  • Ignoring the negative sign when a bracket result is negative → −4 is perfectly valid as a divisor
  • Forgetting to apply the exponent to a negative base: (−2)³ = −8, but −2³ = −8 anyway here — be careful with (−2)² = 4 vs −2² = −4

🔴 Extended

Full Concept

Nested Brackets — The Inside-Out Method

When expressions have brackets inside brackets inside brackets, the temptation is to rush. Don’t. The rule is brutally simple: solve the innermost bracket first. If you have an expression like 2 × { [ (3 + 4)² − 5 ] + 6 }, your step-by-step is:

  1. Innermost: (3 + 4) = 7
  2. Apply the square: 7² = 49
  3. Subtract 5: 49 − 5 = 44
  4. Add 6: 44 + 6 = 50
  5. Multiply by 2: 2 × 50 = 100

Each step reduces the complexity by one layer. If you try to do multiple steps at once, you’ll make mistakes on tricky negatives.

Square Roots in Simplification

Square roots have a special property under multiplication and division:

  • √(a × b) = √a × √b — this only works cleanly when a and b are non-negative
  • √a ÷ √b = √(a ÷ b) — same condition

When you see √ in an expression, treat it like an Order (O in BODMAS) — it sits at the same priority as exponents. Simplify any square root of a perfect square immediately: √144 = 12, √49 = 7. For non-perfect squares, you can sometimes factor them: √50 = √(25 × 2) = 5√2.

How Calculators Evaluate Expressions

Your scientific calculator uses BODMAS exactly. Type 2 + 3 × 4 into a basic calculator and you might get 20 (left-to-right: (2+3)×4 = 20). Type it into a scientific calculator and you get 14 (2 + (3×4) = 14). The CUET exam is always the scientific calculator model — BODMAS, not left-to-right.

The Vinculum — The Hidden Fourth Bracket

A vinculum is a bar over digits (like the line in a fraction, or the bar over a repeating decimal). In BODMAS, anything under a vinculum is treated like a bracket. For example, in 5 − 3̅4̅5̅, the 345 is treated as a single negative number: 5 − (−345) = 350. This shows up in fraction notation and recurring decimal problems.

Distributive Law — The Shortcut That Saves Time

a × (b + c) = a×b + a×c — this lets you bypass brackets entirely. Instead of computing (100 + 37) × 8 by first finding 137 × 8 = 1096, you can do 100×8 + 37×8 = 800 + 296 = 1096. When numbers are close to round values, distribute first. This is also the logic behind the a² − b² = (a+b)(a−b) and (a+b)² expansions.

Common Pitfalls with Signs

The trickiest part of BODMAS for most students is managing negative signs through brackets:

  • −(−4) = +4 (double negative flips positive)
  • 5 − (−4) = 5 + 4 = 9
  • −3 × (−4) = +12 (negative × negative = positive)
  • −3 × 4 = −12

When a minus sign sits directly before a bracket, it flips every sign inside. So −(2x − 3y + 4z) = −2x + 3y − 4z. This trips up even strong students under time pressure.

Multiple Approaches

Evaluating 144 ÷ 3 × 4:

  • Standard: Left to right: 144 ÷ 3 = 48, then 48 × 4 = 192
  • Shortcut: Multiply denominators first: 144 × 4 ÷ 3 = 576 ÷ 3 = 192 (same result, fewer steps)

Evaluating 999 × 7 + 999 × 3:

  • Standard: 999 × 7 = 6993, 999 × 3 = 2997, sum = 9990
  • Shortcut: 999 × (7+3) = 999 × 10 = 9990 — distributive law

CUET-Level Problems

Q1: Simplify: 18 − [24 ÷ {5 − (3 − 2)}] Working: Inner brackets: (3 − 2) = 1. Then {5 − 1} = 4. Then [24 ÷ 4] = 6. Then 18 − 6 = 12. Answer: 12

Q2: Find the value of 5 × { [ (2³ + 3²) ÷ 7 ] − √16 } Working: Orders: 2³ = 8, 3² = 9, so (8 + 9) = 17. Keep 17 ÷ 7 as the fraction 17/7. √16 = 4. So inside: (17 ÷ 7) − 4 = (17/7) − (28/7) = (17−28)/7 = −11/7. Then 5 × (−11/7) = −55/7 = −7.86 (or −55/7 as fraction). Answer: −55/7

Tricky Cases

  • Zero in the denominator — expression becomes undefined (e.g., 8 ÷ 0 is NOT infinity, it’s undefined). Watch for bracket results that equal zero.
  • Long expressions with all operations: Always write each step down. Attempting to do BODMAS mentally is the #1 cause of errors.
  • Decimal division before integer multiplication: 2.5 × 4 ÷ 0.5 — handle decimals carefully, work left to right.
  • Negative numbers raised to powers: (−3)² = 9 but −3² = −9. The brackets matter enormously.

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Sources & verification

📐 Diagram Reference

A complex nested bracket expression broken down into a tree diagram, each branch showing which operation is solved at each step

Diagrams are generated per-topic using AI. Support for AI-generated educational diagrams coming soon.