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Mathematics 3% exam weight

Circles

Part of the CUET UG study roadmap. Mathematics topic math-004 of Mathematics.

Circles

🟢 Lite — Quick Review (1h–1d)

Rapid summary for last-minute revision.

Circles — Key Facts for CUET • Standard form: (x − h)² + (y − k)² = r² — centre (h, k), radius r; always verify r > 0 before answering. • Most tested CUET concept: Finding whether a given line is a tangent, secant, or external to a circle by comparing the perpendicular distance from the centre to the line (d) with the radius r: d > r → external; d = r → tangent; d < r → secant. • Common mistake: Incorrectly applying the square root when finding radius from general form x² + y² + 2gx + 2fy + c = 0 — r = √(g² + f² − c) requires g² + f² > c, not forgetting the sign of c. • Key technique: For any tangent to the circle x² + y² = r² at point (x₁, y₁) on it, use the T = 0 shortcut: xx₁ + yy₁ = r². This avoids deriving the slope-intercept form. • Important exception: When a problem states a point lies ON the circle, the length of tangent formula gives zero — confirming degenerate tangent case; do not treat this as “no tangent exists.” • Most frequent question type: Given the centre and radius, write the equation; or given three non-collinear points, find the circle’s equation using the determinant method. ⚡ Exam tip: In coordinate geometry MCQs with a line and a circle, always check whether the point of intersection is real before applying any tangent formula — a quick discriminant check (b² − 4ac) on the substitution will instantly tell you how many intersection points exist.


🟡 Standard — Regular Study (2d–2mo)

Standard content for students with a few days to months.

Circles — CUET Study Guide

A circle is the set of all points in a plane at a fixed distance (radius r) from a fixed point (centre). The standard equation with centre (h, k) and radius r is (x − h)² + (y − k)² = r². Expanding gives the general form: x² + y² + 2gx + 2fy + c = 0, where the centre is (−g, −f) and the radius is r = √(g² + f² − c), valid only when g² + f² > c. If g² + f² = c, the radius is zero (a point circle); if g² + f² < c, the equation represents no real locus.

For the circle with endpoints of a diameter at A(x₁, y₁) and B(x₂, y₂), the equation is (x − x₁)(x − x₂) + (y − y₁)(y − y₂) = 0. This form directly encodes the right-angle property: every angle inscribed in a semicircle is 90°.

The tangent to circle x² + y² = r² at a point P(x₁, y₁) on the circle is given by xx₁ + yy₁ = r² (the T = 0 form). For the general circle x² + y² + 2gx + 2fy + c = 0, the tangent at (x₁, y₁) on it is: xx₁ + yy₁ + g(x + x₁) + f(y + y₁) + c = 0. Alternatively, use the slope form: a tangent of slope m to circle x² + y² = r² is y = mx ± r√(1 + m²).

The length of tangent from an external point P(x₁, y₁) to the circle is √(x₁² + y₁² + 2gx₁ + 2fy₁ + c). This is derived from the power of a point theorem: PT² = PO² − r².

Director circle of ellipse (x²/a²) + (y²/b²) = 1 is x² + y² = a² + b² — the locus of points from which perpendicular tangents can be drawn to the ellipse.

Solved Example 1: Find the tangent to x² + y² = 25 at the point (3, 4).

  • Using T = 0: xx₁ + yy₁ = 25 → 3x + 4y = 25 ✓
  • Check: (3, 4) satisfies 3² + 4² = 9 + 16 = 25 ✓

Solved Example 2: A point (6, 8) is 10 units from the origin. Is it outside, on, or inside the circle x² + y² = 36?

  • d² = 6² + 8² = 36 + 64 = 100 > 36 → outside the circle of radius 6.
  • Length of tangent from this point to the smaller circle = √(100 − 36) = √64 = 8.

🔴 Extended — Deep Study (3mo+)

Comprehensive coverage for students on a longer timeline.

Circles — Comprehensive CUET Notes

Family of circles: Two basic families are important: (1) Circles with fixed centre and variable radius (concentric family): (x − h)² + (y − k)² = λ². (2) Circles passing through a fixed point and satisfying additional conditions produce linear combinations of the two circles S ≡ x² + y² + 2gx + 2fy + c = 0 and S₁ ≡ x² + y² + 2g₁x + 2f₁y + c₁ = 0: the family S + λS₁ = 0 passes through the intersection points of S and S₁.

Radical axis and radical centre: For two circles S = 0 and S’ = 0, the radical axis is S − S’ = 0, a straight line perpendicular to the line joining the two centres. For three circles, the point of intersection of their three pairwise radical axes is the radical centre — the unique point having equal power with respect to all three circles.

Common tangent to two circles: For circles with centres C₁, C₂ and radii r₁, r₂ (r₁ ≠ r₂), the number of common tangents is:

  • |r₁ − r₂| < d < r₁ + r₂ → 2 direct common tangents and 2 transverse (cross) tangents.
  • d = r₁ + r₂ → 2 direct tangents (transverse coincide)
  • d = |r₁ − r₂| → 2 transverse tangents (direct coincide, external tangents become internal)
  • d > r₁ + r₂ → 4 tangents
  • d < |r₁ − r₂| → 0 real tangents (one circle lies inside the other)

Advanced solved example: Find the equation of the circle passing through the intersection points of x² + y² = 25 and x² + y² − 4x − 2y + 4 = 0, and also through (3, 2).

  • S₁: x² + y² − 25 = 0; S₂: x² + y² − 4x − 2y + 4 = 0
  • Family: S₁ + λS₂ = 0 → (1+λ)(x² + y²) − 4λx − 2λy + (4λ − 25) = 0
  • Since (3, 2) lies on the required circle: (1+λ)(9+4) − 12λ − 4λ + (4λ − 25) = 0 → 13(1+λ) − 16λ + 4λ − 25 = 0 → 13 + 13λ − 12λ − 25 = 0 → λ + (−12) = 0 → λ = 12
  • Substituting λ = 12: 13(x² + y²) − 48x − 24y + (48 − 25) = 0 → 13x² + 13y² − 48x − 24y + 23 = 0
  • This is the required circle equation.

Parametric representation: A circle (x − h)² + (y − k)² = r² can be parametrized as x = h + r cosθ, y = k + r sinθ. This is especially useful for problems involving chords or tangents expressed in terms of a parameter θ.

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